A123591 a(n) = ((2^n - 1)^(2^n) - 1)/(2^n)^2.
-1, 0, 5, 90075, 25657845139503479, 516742576223066713590751888575037849059948015
Offset: 0
Keywords
Links
- G. C. Greubel, Table of n, a(n) for n = 0..8
Programs
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Magma
[((2^n - 1)^(2^n) - 1)/(2^n)^2: n in [0..7]]; // G. C. Greubel, Oct 26 2017
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Mathematica
Table[((2^n-1)^(2^n)-1)/(2^n)^2,{n,0,7}]
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PARI
for(n=0,7, print1(((2^n - 1)^(2^n) - 1)/(2^n)^2, ", ")) \\ G. C. Greubel, Oct 26 2017
Formula
a(n) = ((2^n - 1)^(2^n) - 1)/(2^n)^2.
a(n) = A085606(2^n)/(2^n)^2.
Extensions
More terms from Alexander Adamchuk, Jan 22 2007
Comments