cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A127938 Number of arithmetic progressions of 2 or more nonnegative integers, strictly increasing with sum n.

Original entry on oeis.org

1, 1, 3, 2, 3, 6, 4, 4, 8, 7, 6, 11, 7, 8, 15, 9, 9, 17, 10, 13, 20, 13, 12, 22, 15, 15, 24, 18, 15, 32, 16, 18, 29, 20, 22, 36, 19, 22, 34, 27, 21, 42, 22, 26, 46, 27, 24, 45, 27, 34, 45, 31, 27, 52, 35, 35, 50, 34, 30, 64, 31, 36, 59, 38, 40, 65, 34, 40, 60, 51, 36, 71, 37, 43
Offset: 1

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Author

Graeme McRae, Feb 08 2007

Keywords

Comments

From Petros Hadjicostas, Sep 28 2019: (Start)
We want to find the number of pairs of integers (b, w) such that b >= 0 and w >= 1 and there is an integer m >= 1 so that m*b + (1/2)*m*(m-1)*w = n.
If we insist that b > 0, we get A049982 (= number of arithmetic progressions of 2 or more positive integers, strictly increasing with sum n). The number of integers m >= 1 such that (1/2)*m*(m-1)*w = n equals A007862(n) (= number of triangular numbers that divide n).
Thus, to get a(n), we add A049982(n) to A007862(n).
(End)

Examples

			a(10) = 7 because there are five 2-element arithmetic progressions that sum to 10, as well as 1+2+3+4 and 0+1+2+3+4.
		

Crossrefs

Programs

  • PARI
    seq(n)={Vec(sum(k=1, (sqrtint(8*n+1)-1)\2,  x^binomial(k+1, 2)/(x^binomial(k+2, 2) - x^binomial(k+1, 2) - x^(k+1) + 1) + O(x*x^n)))} \\ Andrew Howroyd, Sep 28 2019

Formula

G.f.: x/(x^3 - x - x^2 + 1) + x^3/(x^6 - x^3 - x^3 + 1) + x^6/(x^10 - x^6 - x^4 + 1) + ... = Sum_{k >= 2} x^{t(k-1)}/(x^{t(k)} - x^{t(k-1)} - x^k + 1), where t(k) = A000217(k) is the k-th triangular number. Term k of this generating function generates the number of arithmetic progressions of k nonnegative integers, strictly increasing with sum n.
a(n) = A049982(n) + A007862(n). - Petros Hadjicostas, Sep 28 2019