A128428 Number of distinct prime factors of n^2+1.
1, 1, 2, 1, 2, 1, 2, 2, 2, 1, 2, 2, 3, 1, 2, 1, 3, 2, 2, 1, 3, 2, 3, 1, 2, 1, 3, 2, 2, 2, 3, 2, 3, 2, 2, 1, 3, 2, 2, 1, 2, 2, 3, 2, 2, 2, 4, 2, 2, 2, 2, 2, 3, 1, 3, 1, 3, 2, 2, 2, 2, 2, 3, 2, 2, 1, 3, 2, 2, 2, 2, 3, 4, 1, 3, 2, 3, 2, 2, 2, 3, 2, 4, 1, 2, 2, 3, 2, 3, 1, 3, 2, 3, 1, 2, 2, 3, 3, 3, 2, 2, 2
Offset: 1
Keywords
Examples
a(3) = 2 because 3^2+1 = 2*5.
Links
- Charles R Greathouse IV, Table of n, a(n) for n = 1..10000
Crossrefs
Cf. A193330 (counted with multiplicity).
Programs
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Maple
a:= n-> nops(select(isprime, numtheory[divisors](n^2+1))): seq(a(n), n=1..100); # Alois P. Heinz, Dec 06 2020
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Mathematica
a[n_]:=Length[FactorInteger[n^2 + 1]]
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PARI
a(n)=omega(n^2+1) \\ Charles R Greathouse IV, Jul 31 2011
Formula
a(n) = A001221(n^2+1).
Comments