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This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A137278 Triangle read by rows: g(n,k) = number of ideals of size k in a garland (or double fence) of order n.

Original entry on oeis.org

1, 1, 1, 1, 1, 2, 1, 2, 1, 1, 3, 3, 3, 3, 3, 1, 1, 4, 6, 6, 7, 6, 6, 4, 1, 1, 5, 10, 12, 14, 15, 14, 12, 10, 5, 1, 1, 6, 15, 22, 27, 32, 33, 32, 27, 22, 15, 6, 1, 1, 7, 21, 37, 50, 63, 72, 75, 72, 63, 50, 37, 21, 7, 1, 1, 8, 28, 58, 88, 118, 146, 164, 171, 164, 146, 118, 88, 58, 28, 8, 1
Offset: 0

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Author

Emanuele Munarini, Mar 13 2008

Keywords

Comments

Row n has 2n+1 terms.
Also triangle of bounded variation linear paths of length n having final height k-n (height varies from -n to n). Olivier Gérard, Aug 28 2012
Bounded variation linear paths are path formed from steps 0,1,-1 where the step successions (-1,1) or (1,-1) are not allowed.
Equivalently ternary strings of length n with subwords (0,2) and (2,0) not allowed and total sum k.

Examples

			In the garland
5..6..7..8
o..o..o..o
|\/|\/|\/|
|/\|/\|/\|
o..o..o..o
1..2..3..4
the ideals of size 4 are 1234, 1253, 1254, 1236, 2347, 1348, 2348.
The ternary strings of size 4 with total sum 4 are
0022, 0202, 0220, 2002, 2020, 2200,
0112, 0121, 0211,
1012, 1021, 2011,
1102, 1201, 2101,
1120, 1210, 2110,
1111
Applying the restriction gives 7 possible strings
0112, 0121, 1012, 2101, 1210, 2110, 1111
Triangle begins:
1,
1, 1, 1,
1, 2, 1, 2, 1,
1, 3, 3, 3, 3, 3, 1,
1, 4, 6, 6, 7, 6, 6, 4, 1,
1, 5, 10, 12, 14, 15, 14, 12, 10, 5, 1,
1, 6, 15, 22, 27, 32, 33, 32, 27, 22, 15, 6, 1,
...
		

References

  • T. S. Blyth and J. C. Varlet, Ockham Algebras, Oxford Science Pub. 1994.
  • E. Munarini, Enumeration of order ideals of a garland, Ars Combin. 76 (2005), 185-192.

Crossrefs

Sequence of row sums is A001333 / A078057.

Formula

G.f.: G(x,t) = (1-x^2*t^2)/(1-(1+x+x^2)*t+x^2*t^2+x^3*t^3).
Recurrence: g(n+3,k+3) = g(n+2,k+3) + g(n+2,k+2) + g(n+2,k+1) - g(n+1,k+1) - g(n,k).