A137904 -id:A137904 - cp's OEIS frontend

A137937 A137904(n) - A137575(n).

0, 0, 3, 4, 5, 6, 7, 8, 9, 10, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86

Offset: 0

Paul Curtz, Apr 30 2008

To have 0 upon vertical 2, 10, 18, 36, 54, 86 (noble gases) is not a problem (with the help of A137583. A (second) 0 upon 1, 3, 11, 19, 37, 55, 87 (alkali metals), seems paradoxal. Is 120 terms (elements) sequence 0, 0, 1, 2, .. 117, 118 credible? This leads to a row 0 (0 upon hydrogen, 0 upon helium). Two common points with Janet periodic table elements.

60 terms: another, with A137913, theoritical companion to A137904.

Cf. A134984, A137575, A137904.

A137913 prepended with 0, 0.

A137913 Rows 2, 4, 6 of Mendeleyev-Seaborg (extended to 32 columns) periodic table elements.

Original entry on oeis.org

3, 4, 5, 6, 7, 8, 9, 10, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86

Offset: 0

Paul Curtz, Apr 30 2008

58 terms. Companion of A137904(60 terms). Both "well" ordered give 118 terms sequence (increasing) 1 to 118;19-10=9, 55-36=19, a(n) differences lead to difference 3 before a(0)=3. Hence neutral element 0.

Cf. A134984, A135559.

cp's OEIS Frontend

A137937 A137904(n) - A137575(n).

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