cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A207359 Indices n, not squarefree, where A055231(n) = A055231(n-A055231(n)).

Original entry on oeis.org

9, 45, 63, 99, 117, 153, 171, 207, 261, 279, 289, 315, 333, 369, 387, 423, 477, 495, 531, 549, 585, 603, 639, 657, 676, 693, 711, 747, 765, 801, 819, 855, 873, 909, 927, 963, 981, 1017, 1035, 1071, 1143, 1179, 1197, 1233, 1251, 1287, 1305, 1341, 1359, 1395
Offset: 1

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Author

Michel Lagneau, Feb 17 2012

Keywords

Comments

A055231(n) is the powerfree part of n. This sequence is infinite because all numbers of the form n = 9p, where p is a prime > 3, are in the sequence : A055231(9p) = p and A055231(9p - p) = A055231(8p) = p. The positive numbers of A055792 are also in the sequence because A055792(n) are squares and A055792(n)-1 are also squares.

Examples

			63 is in the sequence because A055231(63) = A055231(7*3^2) = 7, A055231(63 - 7) = A055231(56) = A055231(7*2^3) = 7.
		

Crossrefs

Programs

A207360 Numbers n, not squarefree, satisfying A055231(n) = A055231(n + A055231(n)).

Original entry on oeis.org

8, 40, 56, 88, 104, 136, 152, 184, 232, 248, 280, 288, 296, 328, 344, 376, 424, 440, 472, 488, 520, 536, 568, 584, 616, 632, 664, 675, 680, 712, 728, 760, 776, 808, 824, 856, 872, 904, 920, 952, 1016, 1048, 1064, 1096, 1112, 1144, 1160, 1192, 1208, 1240, 1256
Offset: 1

Views

Author

Michel Lagneau, Feb 17 2012

Keywords

Comments

A055231(n) is the powerfree part of n.
This sequence is infinite because the numbers of the form n = 8p, where p is prime, are in the sequence : A055231(8p) = p and A055231(8p + p) = A055231(9p) = p.
The numbers such that n and n+1 are a pair of consecutive powerful numbers (the again infinite A060355) are also in the sequence because A055231 (A060355(n)) = A055231(A060355 (n+1)) = 1.

Examples

			136 is in the sequence because A055231(136) = A055231(17*2^3) = 17, A055231(136 + 17) = A055231(153) = A055231(17*3^2) = 17.
		

Crossrefs

Programs

Showing 1-2 of 2 results.