A147773 a(n) = round((n^n)^(1/3)).
1, 2, 3, 6, 15, 36, 94, 256, 729, 2154, 6583, 20736, 67156, 223150, 759375, 2642246, 9387369, 34012224, 125537306, 471556032, 1801088541, 6989288907, 27536796143, 110075314176, 446169698824, 1832746290156, 7625597484987, 32122422687591
Offset: 1
Keywords
Links
- Chai Wah Wu, Table of n, a(n) for n = 1..500
Programs
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Mathematica
lst={};Do[AppendTo[lst,Round[(n^n)^(1/3)]],{n,40}];lst
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Python
from gmpy2 import iroot_rem def A147773(n): i, j = iroot_rem(n**n,3) return int(i+int(8*j >= 6*i*(2*i+1)+1)) # Chai Wah Wu, Aug 16 2016