cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A147796 Number of consistent sets of 3 irreflexive binary order relationships over n objects.

Original entry on oeis.org

6, 152, 940, 3600, 10570, 26096, 56952, 113280, 209550, 365640, 608036, 971152, 1498770, 2245600, 3278960, 4680576, 6548502, 8999160, 12169500, 16219280, 21333466, 27724752, 35636200, 45344000, 57160350, 71436456, 88565652, 108986640, 133186850, 161705920
Offset: 3

Views

Author

R. H. Hardin, May 04 2009

Keywords

Comments

From Petros Hadjicostas, Apr 10 2020: (Start)
Here is a proof of the formula for a(n). There are n*(n-1) irreflexive binary order relationships among n distinct objects and binomial(n*(n-1), 3) 3-sets of such relationships.
We first exclude the 3-sets that contain both relationships of the form x < y and y < x (with x <> y), and there are (n*(n-1)/2) *(n*(n-1) - 2) such 3-sets.
Next we exclude the 3-sets that contain all the relationships of the form x < y, y < z, and z < x (with x, y, z distinct), and there are 2*binomial(n,3) of these.
The two groups of excluded 3-sets do not overlap, and the formula has been proved.
It seems that a(n) = A081064(n,3) = number of labeled acyclic directed graphs with n nodes and k = 3 arcs (see Rodionov (1992)). The reason is that we may label the graphs with the n objects and draw an arc from X towards Y if and only if X < Y. The 3 arcs of the directed graph correspond to the 3-set of binary order relationships and they are consistent because the directed graph is acyclic.
(End)

Examples

			From _Petros Hadjicostas_, Apr 10 2020: (Start)
For n = 3, consider objects a, b, c. There are 3*2 = 6 irreflexive binary order relationships among these objects (a < b, b < a, a < c, c < a, b < c, c < b). For a set of 3 such sets of binary relationships to be consistent, x < y and y < x should not appear together, and x < y, y < z, and z < x should not be together. We have the following sets of 3 such relationships that are consistent: {x < y, y < z, x < z}, where (x,y,z) is in S_3. Thus, a(3) = |S_3| = 3! = 6. (End)
		

Crossrefs

Related sequences for the number of consistent sets of k irreflexive binary order relationships over n objects: A147817 (k = 4), A147821 (k = 5), A147860 (k = 6), A147872 (k = 7), A147881 (k = 8), A147883 (k = 9), A147964 (k = 10).
Column k = 3 of A081064.

Programs

  • Maple
    a := n -> (1/6)*n*(n-1)*(n-2)*(n^3-5*n-6):
    seq(a(n), n=3..32); # Peter Luschny, Apr 11 2020

Formula

a(n) = binomial(n*(n-1), 3) - n*(n-1)*(n*(n-1) - 2)/2 - 2*binomial(n,3) = binomial(n,3) * (n^3 - 5*n - 6). - Petros Hadjicostas, Apr 10 2020
Conjectures from Colin Barker, Apr 11 2020: (Start)
G.f.: 2*x^3*(3 + 55*x + x^2 + x^3) / (1 - x)^7.
a(n) = 7*a(n-1) - 21*a(n-2) + 35*a(n-3) - 35*a(n-4) + 21*a(n-5) - 7*a(n-6) + a(n-7) for n>8.
(End)

Extensions

More terms from Vaclav Kotesovec, Apr 11 2020
Offset changed to n=3 by Petros Hadjicostas, Apr 11 2020