A152836 a(0)=-1; a(n)=n^a(n-1)-a(n-1)^n.

-1, 2, 0, 1, 3, -118

Offset: 0

Author

Vladimir Joseph Stephan Orlovsky, Dec 14 2008

Keywords

• sign
• fini
• less

Comments

Sequence is finite because followup terms are fractions. - R. J. Mathar, Jun 19 2021

Crossrefs

Cf. A084964, A152832, A152833, A152835

Programs

Mathematica

lst={};a=1;Do[a=n^a-a^n;AppendTo[lst,a],{n,0,5}];lst
nxt[{n_,a_}]:={n+1,(n+1)^a-a^(n+1)}; NestList[nxt,{0,-1},5][[All,2]] (* Harvey P. Dale, Jun 06 2022 *)

Extensions

Definition corrected by N. J. A. Sloane, Jan 11 2009

Offset corrected. R. J. Mathar, Jun 19 2021