cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-2 of 2 results.

A153672 Numbers k such that the fractional part of (101/100)^k is greater than 1-(1/k).

Original entry on oeis.org

1, 69, 180, 783, 859, 1803, 10763, 19105, 39568, 50172, 132572, 355146, 1452050, 2245950, 3047334, 3933030, 4165171, 98544173
Offset: 1

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Author

Hieronymus Fischer, Jan 06 2009

Keywords

Comments

Numbers k such that fract((101/100)^k) > 1-(1/k), where fract(x) = x-floor(x).
The next term is greater than 2*10^8.

Examples

			a(2) = 69, since fract((101/100)^69) = 0.9868... > 0.9855... = 1 - (1/69), but fract((101/100)^k) <= 1 - (1/k) for 1 < k < 69.
		

Crossrefs

Programs

  • Mathematica
    Select[Range[1000], FractionalPart[(101/100)^#] >= 1 - (1/#) &] (* G. C. Greubel, Aug 24 2016 *)

Extensions

a(13)-a(18) from Robert Gerbicz, Nov 22 2010

A154137 Greatest number m such that the fractional part of (4/3)^A154133(n) >= 1-(1/m).

Original entry on oeis.org

1, 4, 88, 1228, 187, 4562, 8183, 167378, 35419, 77421, 5593723, 3306511, 83205705, 22413581, 24296709, 35457806, 26593355, 19945016, 80184972, 389460601
Offset: 1

Views

Author

Hieronymus Fischer, Jan 11 2009

Keywords

Examples

			a(3)=88, since 1-(1/89)=0.988764...>fract((4/3)^A154133(3))=fract((4/3)^8)=0.988721...>0.988636...=1-(1/88).
		

Crossrefs

Formula

a(n):=floor(1/(1-fract((4/3)^A154133(n)))), where fract(x) = x-floor(x).

Extensions

a(11)-a(20) from Robert Price, May 10 2012
Showing 1-2 of 2 results.