A155495 Triangle read by rows: t(n,m) = binomial(2*n,2*m) * binomial(n,m).
1, 1, 1, 1, 12, 1, 1, 45, 45, 1, 1, 112, 420, 112, 1, 1, 225, 2100, 2100, 225, 1, 1, 396, 7425, 18480, 7425, 396, 1, 1, 637, 21021, 105105, 105105, 21021, 637, 1, 1, 960, 50960, 448448, 900900, 448448, 50960, 960, 1, 1, 1377, 110160, 1559376, 5513508, 5513508, 1559376, 110160, 1377, 1
Offset: 0
Examples
Table starts: 1; 1, 1; 1, 12, 1; 1, 45, 45, 1; 1, 112, 420, 112, 1; 1, 225, 2100, 2100, 225, 1; 1, 396, 7425, 18480, 7425, 396, 1; 1, 637, 21021, 105105, 105105, 21021, 637, 1; 1, 960, 50960, 448448, 900900, 448448, 50960, 960, 1; 1, 1377, 110160, 1559376, 5513508, 5513508, 1559376, 110160, 1377, 1; 1, 1900, 218025, 4651200, 26453700, 46558512, 26453700, 4651200, 218025, 1900, 1;
Links
- Robert Israel, Table of n, a(n) for n = 0..10010(rows 0 to 140, flattened)
Programs
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Magma
[Binomial(n, k)*Binomial(2*n, 2*k): k in [0..n], n in [0..12]]; // G. C. Greubel, May 29 2021
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Maple
seq(seq(binomial(2*n,2*m)*binomial(n,m), m=0..n),n=0..10); # Robert Israel, Jun 12 2017
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Mathematica
T[n_, k_]:= Binomial[2*n,2*k]*Binomial[n,k]; Table[T[n, k], {n,0,12}, {k,0,n}]//Flatten Abs[Flatten[Table[CoefficientList[HypergeometricPFQ[{-n,-n,-n+1/2}, {1,1/2}, x], x], {n, 1, 20}]]] (* or *) T[n_,k_]:= (-1)^k*Coefficient[HypergeometricPFQ[{-n,-n,-n+1/2}, {1,1/2}, x], x^k] (* John M. Campbell, Oct 23 2011 *)
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Sage
flatten([[binomial(n, k)*binomial(2*n, 2*k) for k in (0..n)] for n in (0..12)]) # G. C. Greubel, May 29 2021
Formula
T(n, k) = binomial(n, k)*binomial(2*n, 2*k).
Sum_{k=0..n} T(n, k) = A288470(n).
Comments