cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A158774 a(n) = 80*n^2 - 1.

Original entry on oeis.org

79, 319, 719, 1279, 1999, 2879, 3919, 5119, 6479, 7999, 9679, 11519, 13519, 15679, 17999, 20479, 23119, 25919, 28879, 31999, 35279, 38719, 42319, 46079, 49999, 54079, 58319, 62719, 67279, 71999, 76879, 81919, 87119, 92479, 97999, 103679, 109519, 115519, 121679
Offset: 1

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Author

Vincenzo Librandi, Mar 26 2009

Keywords

Comments

The identity (80*n^2 - 1)^2 - (1600*n^2 - 40)*(2*n)^2 = 1 can be written as a(n)^2 - A158773(n)*A005843(n)^2 = 1.

Crossrefs

Programs

  • Magma
    I:=[79, 319, 719]; [n le 3 select I[n] else 3*Self(n-1)-3*Self(n-2)+1*Self(n-3): n in [1..40]]; // Vincenzo Librandi, Feb 20 2012
    
  • Mathematica
    LinearRecurrence[{3, -3, 1}, {79, 319, 719}, 50] (* Vincenzo Librandi, Feb 20 2012 *)
    80*Range[40]^2-1 (* Harvey P. Dale, Apr 21 2018 *)
  • PARI
    for(n=1, 40, print1(80*n^2 - 1", ")); \\ Vincenzo Librandi, Feb 20 2012

Formula

From R. J. Mathar, Jul 26 2009: (Start)
G.f.: x*(-79 - 82*x + x^2)/(x-1)^3.
a(n) = 3*a(n-1) - 3*a(n-2) + a(n-3). (End)
From Amiram Eldar, Mar 24 2023: (Start)
Sum_{n>=1} 1/a(n) = (1 - cot(Pi/(4*sqrt(5)))*Pi/(4*sqrt(5)))/2.
Sum_{n>=1} (-1)^(n+1)/a(n) = (cosec(Pi/(4*sqrt(5)))*Pi/(4*sqrt(5)) - 1)/2. (End)
From Elmo R. Oliveira, Jan 25 2025: (Start)
E.g.f.: exp(x)*(80*x^2 + 80*x - 1) + 1.
a(n) = A158491(2*n). (End)

Extensions

Edited by R. J. Mathar, Jul 26 2009
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