A159458 Numbers m such that m^2 divides A159068(m), where A159068(m) = Sum_{k=1..m} binomial(m,k) * gcd(m,k).
1, 2, 3, 11, 33, 309, 665, 1461, 2323, 6789
Offset: 1
Programs
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PARI
is(m) = sum(k=1, m, binomial(m, k)*gcd(k, m))%m^2 == 0; \\ Jinyuan Wang, Aug 10 2021
Extensions
4 more terms from R. J. Mathar, Apr 16 2009
a(10)=6789 from Ray Chandler, Jun 19 2009
Comments