A160117 Number of "ON" cells after n-th stage in simple 2-dimensional cellular automaton (see Comments for precise definition).
0, 1, 9, 13, 41, 49, 101, 113, 189, 205, 305, 325, 449, 473, 621, 649, 821, 853, 1049, 1085, 1305, 1345, 1589, 1633, 1901, 1949, 2241, 2293, 2609, 2665, 3005, 3065, 3429, 3493, 3881, 3949, 4361, 4433, 4869, 4945, 5405, 5485, 5969, 6053, 6561, 6649, 7181, 7273
Offset: 0
Keywords
Examples
If we label the generations of cells turned ON by consecutive numbers we get the cell pattern shown below: 9...9...9...9...9 .888.888.888.888. .878.878.878.878. .886668666866688. 9..656.656.656..9 .886644464446688. .878.434.434.878. .886644222446688. 9..656.212.656..9 .886644222446688. .878.434.434.878. .886644464446688. 9..656.656.656..9 .886668666866688. .878.878.878.878. .888.888.888.888. 9...9...9...9...9 At the first generation, only the central "1" is ON, so a(1) = 1. At the second generation, we turn ON eight cells around the central cell, leading to a(2) = a(1)+8 = 9. At the third generation, we turn ON four peninsula cells, so a(3) = a(2)+4 = 13. At the fourth generation, we turn ON the cells around the cells turned ON at the third generation, so a(4) = a(3)+28 = 41. At the 5th generation, we turn ON four peninsula cells and four bridge cells, so a(5) = a(4)+8 = 49.
Links
- Alois P. Heinz, Table of n, a(n) for n = 0..1000
- David Applegate, Omar E. Pol and N. J. A. Sloane, The Toothpick Sequence and Other Sequences from Cellular Automata, Congressus Numerantium, Vol. 206 (2010), 157-191. [There is a typo in Theorem 6: (13) should read u(n) = 4.3^(wt(n-1)-1) for n >= 2.]
- N. J. A. Sloane, Catalog of Toothpick and Cellular Automata Sequences in the OEIS
- Index entries for sequences related to cellular automata
Programs
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Maple
a:= proc(n) local r; r:= irem(n, 2); `if`(n<2, n, 5+(n-r)*((7*n-3*r)/2-5)) end: seq(a(n), n=0..80); # Alois P. Heinz, Sep 16 2011
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Mathematica
a[0] = 0; a[1] = 1; a[n_] := If[EvenQ[n], (7n^2 - 10n + 10)/2, (7n^2 - 20n + 23)/2]; Table[a[n], {n, 0, 80}] (* Jean-François Alcover, Jul 16 2015, after Nathaniel Johnston *)
Formula
a(2n) = 5 + 2n(7n-5) for n>=1, a(2n+1) = 5 + 2n(7n-3) for n>=1. - Nathaniel Johnston, Nov 06 2010
G.f.: x*(x^2+1)*(4*x^3+x^2+8*x+1)/((x+1)^2*(1-x)^3). - Alois P. Heinz, Sep 16 2011
Extensions
a(10) - a(27) from Nathaniel Johnston, Nov 06 2010
a(28) - a(47) from Alois P. Heinz, Sep 16 2011
Comments