cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A165774 Largest solution to phi(x) = n!, where phi() is Euler totient function (A000010).

Original entry on oeis.org

2, 6, 18, 90, 462, 3150, 22050, 210210, 1891890, 19969950, 219669450, 2847714870, 37020293310, 520843112790, 7959363061650, 135309172048050, 2300255924816850, 41996101027370490, 797925919520039310, 16504589035937252250, 347097774991217099850, 7751850308137181896650, 179602728970220622816750, 4493489228616853106091450, 112337230715421327652286250, 2958213742172761628176871250, 79871771038664563960775523750, 2279417465795734863803670716250
Offset: 1

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Author

M. F. Hasler, Oct 04 2009

Keywords

Comments

All solutions to phi(x) = n! belong to the interval [n!,(n+1)!] and are listed in the n-th row of A165773 (when written as table with row lengths A055506). Thus this sequence gives the last element in these rows, i.e., a(n) = A165773(Sum_{k=1..n} A055506(k)).
All terms in this sequence are even, since if x is an odd solution to phi(x) = n!, then 2x is a larger solution because phi(2x) = phi(2)*phi(x) = phi(x).
Most terms (and any term divisible by 4) are divisible by 3, since if x = 2^k*y is a solution with k>1 and gcd(y,2*3) = 1, then x*3/2 = 2^(k-1)*3*y is a larger solution because phi(2^(k-1)*3) = 2^(k-2)*(3-1) = 2^(k-1) = phi(2^k).
For the same reason, most terms are divisible by 5, since if x=2^k*y is a solution with k>2 and gcd(y,2*5) = 1, then x*5/4 is a larger solution.
Also, any term of the form x = 2^k*3^m*y with k,m>1 must be divisible by 7 (else x*7/6 would be a larger solution), and so on.
Experimentally, a(n) = c(n)*(n+1)! with a coefficient c(n) ~ 2^(-n/10) (e.g., c(1) = c(2) = 1, c(10) ~ 0.5).

Examples

			a(1) = 2 is the largest among the A055506(1) = 2 solutions {1,2} to phi(n) = 1! = 1.
a(4) = 90 is the largest among the A055506(4) = 10 solutions {35, 39, 45, 52, 56, 70, 72, 78, 84, 90} to phi(n) = 4! = 24.
See A165773 for more examples.
		

Crossrefs

Programs

Extensions

Edited and terms a(12)-a(28) added by Max Alekseyev, Jan 26 2012, Jul 09 2014