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This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A167860 Primes p dividing every A167859(m) from m=(p-1)/2 to m=(p-1).

Original entry on oeis.org

7, 47, 191, 383, 439, 1151, 1399, 2351, 2879, 3119, 3511, 3559, 4127, 5087, 5431, 6911, 8887, 9127, 9791, 9887, 12391, 13151, 14407, 15551, 16607, 19543, 20399, 21031, 21319, 21839, 23039, 25391, 26399, 28087, 28463, 28711, 29287, 33223, 39551, 43103, 44879, 46271
Offset: 1

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Author

Alexander Adamchuk, Nov 13 2009

Keywords

Comments

Apparently A167860 is a subset of primes of the form 8*k + 7 (A007522).
Every A167859(m) from m=(p-1)/2 to m=(p-1) is divisible by prime p belonging to A167860.
7^3 divides A167859(13) and 7^2 divides A167859(10)-A167859(13).
Every A167859(m) from m=(kp-1 - (p-1)/2) to m=(kp-1) is divisible by prime p from A167860.
Every A167859(m) from m=((p^2-1)/2) to m=(p^2-1) is divisible by prime p from A167860. For p=7 every A167859(m) from m=((p^3-1)/2) to m=(p^3-1) and from m=((p^4-1)/2) to m(p^4-1)is divisible by p^2.

Crossrefs

Programs

  • Maple
    A167859 := proc(n)
        option remember;
        if n <= 1 then
            add( (binomial(2*k, k)/2^k)^2, k=0..n) ;
            4^n*% ;
        else
            4*(5*n^2 - 4*n + 1)*procname(n-1) - 16*(2*n - 1)^2*procname(n-2) ;
            %/n^2 ;
        end if;
    end proc:
    isA167860 := proc(p)
        local m ;
        for m from (p-1)/2 to p-1 do
            if modp(A167859(m),p) > 0 then
                return false;
            end if;
        end do:
        true ;
    end proc:
    A167860 := proc(n)
        option remember ;
        if n = 0 then
            2;
        else
            p := nextprime(procname(n-1)) ;
            while not isA167860(p) do
                p := nextprime(p) ;
            end do ;
            return p;
        end if;
    end proc:
    seq(A167860(n),n=1..10) ; # R. J. Mathar, Jan 22 2025
  • PARI
    is(p) = if(isprime(p)&&p%2, my(m=Mod(1, p), s=m); for(k=1, p\2, s+=(m*=(2*k-1)/k)^2); !s, 0); \\ Jinyuan Wang, Jul 24 2022

Extensions

More terms from Jinyuan Wang, Jul 24 2022