A168095 a(n) = number of natural numbers m such that n - 5 <= m <= n + 5.

5, 6, 7, 8, 9, 10, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11

Offset: 0

Author

Jaroslav Krizek, Nov 18 2009

Keywords

• nonn
• less

Comments

Generalization: If a(n,k) = number of natural numbers m such that n - k <= m <= n + k (k >= 1) then a(n,k) = a(n-1,k) + 1 = n + k for 0 <= n <= k, a(n,k) = a(n-1,k) = 2k + 1 for n >= k + 1 (see, e.g., A158799).

Links

• Index entries for linear recurrences with constant coefficients, signature (1).

Crossrefs

Cf. A000027.

Programs

Mathematica

CoefficientList[Series[(5 - 4*x - x^7)/(1 - x)^2, {x, 0, 25}], x] (* G. C. Greubel, Jul 12 2016 *)

Formula

a(n) = 5 + n for 0 <= n <= 5, a(n) = 11 for n >= 6.

G.f.: (5 - 4*x - x^7)/(1-x)^2. - G. C. Greubel, Jul 12 2016