A222235 In the number n, replace all (decimal) digits '3' with '5' and vice versa.
0, 1, 2, 5, 4, 3, 6, 7, 8, 9, 10, 11, 12, 15, 14, 13, 16, 17, 18, 19, 20, 21, 22, 25, 24, 23, 26, 27, 28, 29, 50, 51, 52, 55, 54, 53, 56, 57, 58, 59, 40, 41, 42, 45, 44, 43, 46, 47, 48, 49, 30, 31, 32, 35, 34, 33, 36, 37, 38, 39, 60, 61, 62, 65, 64, 63, 66, 67, 68, 69, 70, 71, 72, 75, 74, 73
Offset: 0
Links
- Vincenzo Librandi, Table of n, a(n) for n = 0..1000
Programs
-
Mathematica
a[n_]:= IntegerDigits[n]/.{3->5, 5->3} // FromDigits; Table[a[n], {n, 0, 80}] (* Vincenzo Librandi, Jul 30 2013 *)
-
PARI
A222235(n,d=[0,1,2,5,4,3,6,7,8,9])={sum(i=1,#n=digits(n),d[n[i]+1]*10^(#n-i),!n*d[1])} \\ N.B.: digits(0)=[] in PARI (v.2.6)
Comments