cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A175424 a(n) is the number of steps of iterations of {(((D_k^D_(k-1))^D_(k-2))^...)^D_1, where D_k is the k-th digit D of number r and k is the number of digits of number r in decimal expansion of r (A055642)} needed to reach a single-digit number starting at r = n, or a(n) = -1 if a single-digit number is never reached.

Original entry on oeis.org

0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, -1, -1, 3, 3, 2, 1, 1, 1, 4, 3, -1, -1, 3, 3, 3, 1, 1, 2, 2, 3, 3, 3, 2, 2, 2, 1, 1, 2, 3, 2, 4, 3, 2, 3, 2, 1, 1, 3, 3, 2, 3, 3, 3, 3, 2, 1, 1, 4, 3, 3, 3, 3, 3, 2, 3, 1, 1, 3, 2, 3, 2, 3, 2, 2, 2, 1, 1, 3, 3, 3, 3, 2, 2, 2, 2
Offset: 0

Views

Author

Jaroslav Krizek, May 09 2010

Keywords

Comments

Conjecture: max(a(n)) = 4.

Examples

			For n = 33: a(33) = 4 because for the number 33 there are 4 steps of defined iteration: {3^3 = 27}, {7^2 = 49}, {9^4 = 6561}, {((1^6)^5)^6 = 1}.
		

Crossrefs

Programs

  • PARI
    f(n) = if (n, my(d=digits(n), r=d[#d]); if (!vecmin(d), return(0)); forstep (k=#d-1, 1, -1, r = r^d[k];); r); \\ A175420
    findpos(n, list) = {forstep (k=#list, 1, -1, if (list[k] == n, return (k));); return (0);}
    a(n) = {my(list = List(n), nb = 0); while (n >= 10, n = f(n); my(k=findpos(n, list)); nb++; if (k, if (k==#list-1, if (list[k]<10, return (nb), return(-1)), return(-1));); listput(list, n);); return (nb);} \\ Michel Marcus, Jan 20 2022