cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-7 of 7 results.

A175498 a(1)=1. a(n) = the smallest positive integer not occurring earlier such that a(n)-a(n-1) doesn't equal a(k)-a(k-1) for any k with 2 <= k <= n-1.

Original entry on oeis.org

1, 2, 4, 3, 6, 10, 5, 11, 7, 12, 9, 16, 8, 17, 15, 23, 13, 24, 18, 28, 14, 26, 19, 32, 20, 34, 21, 36, 25, 41, 22, 39, 30, 48, 27, 46, 29, 49, 31, 52, 37, 59, 33, 56, 40, 64, 35, 60, 38, 65, 42, 68, 43, 71, 44, 73, 45, 75, 51, 82, 47, 79, 112, 50, 84, 53, 88, 54, 90, 57, 94, 55, 93, 61, 100, 58, 98, 62, 103, 63, 105, 67
Offset: 1

Views

Author

Leroy Quet, May 31 2010

Keywords

Comments

This sequence is a permutation of the positive integers.
a(n+1)-a(n) = A175499(n).
Conjecture: the lexicographically earliest permutation of {1,2,...n} for which differences of adjacent numbers are all distinct (cf. A131529) has, for n-->infinity, this sequence as its prefix. - Joerg Arndt, May 27 2012

Crossrefs

Programs

  • Haskell
    import Data.List (delete)
    a175498 n = a175498_list !! (n-1)
    a175498_list = 1 : f 1 [2..] [] where
       f x zs ds = g zs where
         g (y:ys) | diff `elem` ds = g ys
                  | otherwise      = y : f y (delete y zs) (diff:ds)
                  where diff = y - x
    -- Reinhard Zumkeller, Apr 25 2015
  • Mathematica
    a[1] = 1; d[1] = 0; k = 1; z = 10000; zz = 120;
    A[k_] := Table[a[i], {i, 1, k}]; diff[k_] := Table[d[i], {i, 1, k}];
    c[k_] := Complement[Range[-z, z], diff[k]];
    T[k_] := -a[k] + Complement[Range[z], A[k]];
    Table[{h = Min[Intersection[c[k], T[k]]], a[k + 1] = a[k] + h, d[k + 1] = h, k = k + 1}, {i, 1, zz}];
    u = Table[a[k], {k, 1, zz}]  (* Clark Kimberling, May 13 2015 *)
  • Python
    A175498_list, l, s, b1, b2 = [1,2], 2, 3, set(), set([1])
    for n in range(3, 10**5):
        i = s
        while True:
            if not (i in b1 or i-l in b2):
                A175498_list.append(i)
                b1.add(i)
                b2.add(i-l)
                l = i
                while s in b1:
                    b1.remove(s)
                    s += 1
                break
            i += 1 # Chai Wah Wu, Dec 15 2014
    

Extensions

More terms from Sean A. Irvine, Jan 27 2011

A257883 Sequence (a(n)) generated by Algorithm (in Comments) with a(1) = 0 and d(1) = 0.

Original entry on oeis.org

0, 1, 3, 2, 5, 9, 4, 10, 6, 11, 8, 15, 7, 16, 14, 22, 12, 23, 17, 27, 13, 25, 18, 31, 19, 33, 20, 35, 24, 40, 21, 38, 29, 47, 26, 45, 28, 48, 30, 51, 36, 58, 32, 55, 39, 63, 34, 59, 37, 64, 41, 67, 42, 70, 43, 72, 44, 74, 50, 81, 46, 78, 111, 49, 83, 52, 87
Offset: 1

Views

Author

Clark Kimberling, May 13 2015

Keywords

Comments

Algorithm: For k >= 1, let A(k) = {a(1), ..., a(k)} and D(k) = {d(1), ..., d(k)}. Begin with k = 1 and nonnegative integers a(1) and d(1). Let h be the least integer > -a(k) such that h is not in D(k) and a(k) + h is not in A(k). Let a(k+1) = a(k) + h and d(k+1) = h. Replace k by k+1 and repeat inductively.
Conjecture: if a(1) is a nonnegative integer and d(1) is an integer, then (a(n)) is a permutation of the nonnegative integers (if a(1) = 0) or a permutation of the positive integers (if a(1) > 0). Moreover, (d(n)) is a permutation of the integers if d(1) = 0, or of the nonzero integers if d(1) > 0.
Guide to related sequences:
a(1) d(1) (a(n)) (d(n))
0 0 A257883 A175499 except for initial terms
1 0 A175498 A175499 except for first term
2 1 A257910 A257909 except for initial terms

Examples

			a(1) = 0, d(1) = 0;
a(2) = 1, d(2) = 1;
a(3) = 3, d(3) = 2;
a(4) = 2, d(4) = -1.
		

Crossrefs

Programs

  • Mathematica
    a[1] = 0; d[1] = 0; k = 1; z = 10000; zz = 120;
    A[k_] := Table[a[i], {i, 1, k}]; diff[k_] := Table[d[i], {i, 1, k}];
    c[k_] := Complement[Range[-z, z], diff[k]];
    T[k_] := -a[k] + Complement[Range[z], A[k]]
    Table[{h = Min[Intersection[c[k], T[k]]], a[k + 1] = a[k] + h,
       d[k + 1] = h, k = k + 1}, {i, 1, zz}];
    u = Table[a[k], {k, 1, zz}]  (* A257883, = -1 + A175498 *)
    Table[d[k], {k, 1, zz}] (* A175499 except that here first term is 0 *)

Formula

a(k+1) - a(k) = d(k+1) for k >= 1.
Also, A257883(n) = -1 + A175498(n) for n >= 1.

A257880 Sequence (d(n)) generated by Rule 1 (in Comments) with a(1) = 2 and d(1) = 0.

Original entry on oeis.org

0, -1, 2, 1, 3, -2, 4, -3, 5, 6, -4, -5, 7, 8, -7, -6, 9, 10, -8, -9, 12, -10, 11, 13, -11, 14, -13, 15, -12, 16, -14, -15, 17, 18, -16, -17, 19, 20, -19, -18, 22, 21, -20, 23, -22, 24, -21, -23, 25, 26, -25, 27, -24, 28, -26, -27, 30, -28, 29, 31, -29, 32
Offset: 1

Views

Author

Clark Kimberling, May 13 2015

Keywords

Comments

This is the sequence (d(n)) of differences associated with the sequence a = A257879.
Rule 1 follows. For k >= 1, let A(k) = {a(1), …, a(k)} and D(k) = {d(1), …, d(k)}. Begin with k = 1 and nonnegative integers a(1) and d(1).
Step 1: If there is an integer h such that 1 - a(k) < h < 0 and h is not in D(k) and a(k) + h is not in A(k), let d(k+1) be the greatest such h, let a(k+1) = a(k) + h, replace k by k + 1, and repeat Step 1; otherwise do Step 2.
Step 2: Let h be the least positive integer not in D(k) such that a(k) + h is not in A(k). Let a(k+1) = a(k) + h and d(k+1) = h. Replace k by k+1 and do Step 1.
Conjecture: if a(1) is an nonnegative integer and d(1) is an integer, then (a(n)) is a permutation of the nonnegative integers (if a(1) = 0) or a permutation of the positive integers (if a(1) > 0). Moreover, (d(n)) is a permutation of the integers if d(1) = 0, or of the nonzero integers if d(1) > 0.
See A257705 for a guide to related sequences.

Examples

			a(1) = 2, d(1) = 0;
a(2) = 1, d(2) = -1;
a(3) = 3, d(3) = 2;
a(4) = 4, d(4) = 1.
		

Crossrefs

Programs

  • Mathematica
    a[1] = 2; d[1] = 0; k = 1; z = 10000; zz = 120;
    A[k_] := Table[a[i], {i, 1, k}]; diff[k_] := Table[d[i], {i, 1, k}];
    c[k_] := Complement[Range[-z, z], diff[k]];
    T[k_] := -a[k] + Complement[Range[z], A[k]];
    s[k_] := Intersection[Range[-a[k], -1], c[k], T[k]];
    Table[If[Length[s[k]] == 0, {h = Min[Intersection[c[k], T[k]]], a[k + 1] = a[k] + h, d[k + 1] = h, k = k + 1}, {h = Max[s[k]], a[k + 1] = a[k] + h, d[k + 1] = h, k = k + 1}], {i, 1, zz}];
    u = Table[a[k], {k, 1, zz}] (* A257879 *)
    Table[d[k], {k, 1, zz}]     (* A257880 *)

Formula

d(k) = a(k) - a(k-1) for k >=2, where a(k) = A257877(k).

A257884 Sequence (a(n)) generated by Algorithm (in Comments) with a(1) = 0 and d(1) = 1.

Original entry on oeis.org

0, 2, 1, 4, 8, 3, 9, 5, 10, 7, 14, 6, 15, 13, 21, 11, 22, 16, 26, 12, 24, 17, 30, 18, 32, 19, 34, 23, 39, 20, 37, 28, 46, 25, 44, 27, 47, 29, 50, 35, 57, 31, 54, 38, 62, 33, 58, 36, 63, 40, 66, 41, 69, 42, 71, 43, 73, 49, 80, 45, 77, 110, 48, 82, 51, 86, 52
Offset: 1

Views

Author

Clark Kimberling, May 13 2015

Keywords

Comments

Algorithm: For k >= 1, let A(k) = {a(1), …, a(k)} and D(k) = {d(1), …, d(k)}. Begin with k = 1 and nonnegative integers a(1) and d(1). Let h be the least integer > -a(k) such that h is not in D(k) and a(k) + h is not in A(k). Let a(k+1) = a(k) + h and d(k+1) = h. Replace k by k+1 and repeat inductively.
Conjecture: if a(1) is an nonnegative integer and d(1) is an integer, then (a(n)) is a permutation of the nonnegative integers (if a(1) = 0) or a permutation of the positive integers (if a(1) > 0). Moreover, (d(n)) is a permutation of the integers if d(1) = 0, or of the nonzero integers if d(1) > 0.
See A257883 for a guide to related sequences.

Examples

			a(1) = 0, d(1) = 1;
a(2) = 2, d(2) = 2;
a(3) = 1, d(3) = -1;
a(4) = 4, d(4) = 3.
		

Crossrefs

Programs

  • Mathematica
    a[1] = 0; d[1] = 1; k = 1; z = 10000; zz = 120;
    A[k_] := Table[a[i], {i, 1, k}]; diff[k_] := Table[d[i], {i, 1, k}];
    c[k_] := Complement[Range[-z, z], diff[k]];
    T[k_] := -a[k] + Complement[Range[z], A[k]]
    Table[{h = Min[Intersection[c[k], T[k]]], a[k + 1] = a[k] + h,
       d[k + 1] = h, k = k + 1}, {i, 1, zz}];
    u = Table[a[k], {k, 1, zz}]  (* A257884 *)
    Table[d[k], {k, 1, zz}]      (* A175499 *)

Formula

a(k+1) - a(k) = d(k+1) for k >= 1.

A257915 Sequence (d(n)) generated by Rule 1 (in Comments) with a(1) = 0 and d(1) = 3.

Original entry on oeis.org

3, 1, 2, -1, 4, -2, 5, -4, 6, -3, 7, -5, 8, -6, 9, -7, 10, -8, -9, 12, 11, -10, 13, -11, 14, -13, 15, -12, 16, -14, -15, 18, 17, -16, 19, -17, 20, -19, -18, 22, 21, -20, 23, -22, 24, -21, 25, -23, 26, -25, 27, -24, 28, -26, -27, 30, -28, 29, 31, -29, 32, -31
Offset: 1

Views

Author

Clark Kimberling, May 12 2015

Keywords

Comments

This is the sequence (d(n)) of differences associated with the sequence a = A257877.
Rule 1 follows. For k >= 1, let A(k) = {a(1), …, a(k)} and D(k) = {d(1), …, d(k)}. Begin with k = 1 and nonnegative integers a(1) and d(1).
Step 1: If there is an integer h such that 1 - a(k) < h < 0 and h is not in D(k) and a(k) + h is not in A(k), let d(k+1) be the greatest such h, let a(k+1) = a(k) + h, replace k by k + 1, and repeat Step 1; otherwise do Step 2.
Step 2: Let h be the least positive integer not in D(k) such that a(k) + h is not in A(k). Let a(k+1) = a(k) + h and d(k+1) = h. Replace k by k+1 and do Step 1.
Conjecture: if a(1) is an nonnegative integer and d(1) is an integer, then (a(n)) is a permutation of the nonnegative integers (if a(1) = 0) or a permutation of the positive integers (if a(1) > 0). Moreover, (d(n)) is a permutation of the integers if d(1) = 0, or of the nonzero integers if d(1) > 0.
See A257705 for a guide to related sequences.

Examples

			a(1) = 0, d(1) = 3;
a(2) = 1, d(2) = 1;
a(3) = 3, d(3) = 2;
a(4) = 2, d(4) = -1.
		

Crossrefs

Programs

  • Mathematica
    a[1] = 0; d[1] = 3; k = 1; z = 10000; zz = 120;
    A[k_] := Table[a[i], {i, 1, k}]; diff[k_] := Table[d[i], {i, 1, k}];
    c[k_] := Complement[Range[-z, z], diff[k]];
    T[k_] := -a[k] + Complement[Range[z], A[k]];
    s[k_] := Intersection[Range[-a[k], -1], c[k], T[k]];
    Table[If[Length[s[k]] == 0, {h = Min[Intersection[c[k], T[k]]], a[k + 1] = a[k] + h, d[k + 1] = h, k = k + 1}, {h = Max[s[k]], a[k + 1] = a[k] + h, d[k + 1] = h, k = k + 1}], {i, 1, zz}];
    u = Table[a[k], {k, 1, zz}]  (* A257877 *)
    Table[d[k], {k, 1, zz}]  (* A257915 *)

Formula

d(k) = a(k) - a(k-1) for k >= 2, where a(k) = A257877(k).

A257918 Sequence (d(n)) generated by Rule 1 (in Comments) with a(1) = 2 and d(1) = 2.

Original entry on oeis.org

2, -1, 3, 1, -2, 4, 5, -3, 6, -4, -5, 7, 8, -7, -6, 9, 10, -8, -9, 12, 11, -10, 13, -11, 14, -13, 15, -12, 16, -14, -15, 18, -16, 17, 19, -17, 20, -19, -18, 22, 21, -20, 23, -22, 24, -21, -23, 25, 26, -24, 27, -25, 28, -26, -27, 30, -28, 29, 31, -29, 32, -31
Offset: 1

Views

Author

Clark Kimberling, May 13 2015

Keywords

Comments

This is the sequence (d(n)) of differences associated with the sequence a = A257882.
Rule 1 follows. For k >= 1, let A(k) = {a(1), …, a(k)} and D(k) = {d(1), …, d(k)}. Begin with k = 1 and nonnegative integers a(1) and d(1).
Step 1: If there is an integer h such that 1 - a(k) < h < 0 and h is not in D(k) and a(k) + h is not in A(k), let d(k+1) be the greatest such h, let a(k+1) = a(k) + h, replace k by k + 1, and repeat Step 1; otherwise do Step 2.
Step 2: Let h be the least positive integer not in D(k) such that a(k) + h is not in A(k). Let a(k+1) = a(k) + h and d(k+1) = h. Replace k by k+1 and do Step 1.
Conjecture: if a(1) is an nonnegative integer and d(1) is an integer, then (a(n)) is a permutation of the nonnegative integers (if a(1) = 0) or a permutation of the positive integers (if a(1) > 0). Moreover, (d(n)) is a permutation of the integers if d(1) = 0, or of the nonzero integers if d(1) > 0.
See A257705 for a guide to related sequences.

Examples

			a(1) = 2, d(1) = 2;
a(2) = 1, d(2) = -1;
a(3) = 4, d(3) = 3;
a(4) = 5, d(4) = 1.
		

Crossrefs

Programs

  • Mathematica
    a[1] = 2; d[1] = 2; k = 1; z = 10000; zz = 120;
    A[k_] := Table[a[i], {i, 1, k}]; diff[k_] := Table[d[i], {i, 1, k}];
    c[k_] := Complement[Range[-z, z], diff[k]];
    T[k_] := -a[k] + Complement[Range[z], A[k]];
    s[k_] := Intersection[Range[-a[k], -1], c[k], T[k]];
    Table[If[Length[s[k]] == 0, {h = Min[Intersection[c[k], T[k]]], a[k + 1] = a[k] + h, d[k + 1] = h, k = k + 1}, {h = Max[s[k]], a[k + 1] = a[k] + h, d[k + 1] = h, k = k + 1}], {i, 1, zz}];
    u = Table[a[k], {k, 1, zz}]  (* A257882 *)
    Table[d[k], {k, 1, zz}]      (* A257918 *)

Formula

d(k) = a(k) - a(k-1) for k >=2, where a(k) = A257882(k).

A334404 a(0)=0; for n>0, a(n) is an integer not previously seen such that the sum of all previous terms plus a(n) equals the smallest prime number not yet created by any previous sum.

Original entry on oeis.org

0, 2, 1, 4, -2, 6, 8, -6, 10, 14, -20, 12, 18, -16, 22, -12, 20, -18, 16, 24, -10, 28, -34, 30, -26, 32, -24, 34, -4, 40, -60, 38, 36, -56, 44, -14, 42, -48, 26, 54, -72, 52, 48, -66, 50, -42, 46, -30, 60, -90, 62, -36, 58, -52, 64, -22, -8, 74, -38, 68, -54, 66, -78, 76, -70, 82, -46
Offset: 0

Views

Author

Scott R. Shannon, Sep 08 2020

Keywords

Comments

See A175499 for an equivalent sequence which sums to the smallest positive integer not yet created.

Examples

			a(1) = 2 as the sum of all previous terms plus a(1) = 0 + 2 = 2, where 2 has not previously occurred in the sequence and the prime 2 has not been previously created.
a(2) = 1 as the sum of all previous terms plus a(2) = 0 + 2 + 1 = 3, where 1 has not previously occurred in the sequence and the prime 3 has not been previously created.
a(3) = 4 as the sum of all previous terms plus a(3) = 0 + 2 + 1 + 4 = 7, where 4 has not previously occurred in the sequence and the prime 7 has not been previously created. Note that the next smallest uncreated prime after a(2) is 5 but that would require a(3) = 2 which is not allowed as a(1) = 2.
a(4) = -2 as the sum of all previous terms plus a(4) = 0 + 2 + 1 + 4 - 2 = 5, where -2 has not previously occurred in the sequence and the prime 5 has not been previously created.
		

Crossrefs

Programs

  • Mathematica
    Nest[Block[{k = 1, s = Total[#[[All, 1]] ], i = 1, p}, While[Nand[FreeQ[#[[All, -1]], Set[p, Prime@ i]], FreeQ[#[[All, 1]], p - s] ], i++]; While[Nand[FreeQ[#[[All, 1]], k], k + s == p], If[k < 0, Set[k, -k + 1], k *= -1]]; Append[#, {k, p}]] &, {{0, 0}}, 66][[All, 1]] (* Michael De Vlieger, Sep 11 2020 *)
Showing 1-7 of 7 results.