A179248 Numbers that have 8 terms in their Zeckendorf representation.

1596, 2206, 2439, 2528, 2562, 2575, 2580, 2582, 2583, 3193, 3426, 3515, 3549, 3562, 3567, 3569, 3570, 3803, 3892, 3926, 3939, 3944, 3946, 3947, 4036, 4070, 4083, 4088, 4090, 4091, 4125, 4138, 4143, 4145, 4146, 4159, 4164, 4166, 4167, 4172, 4174, 4175

Offset: 1

Author

Emeric Deutsch, Jul 05 2010

Keywords

• nonn

Comments

A007895(a(n)) = 8. - Reinhard Zumkeller, Mar 10 2013

Examples

			1596 =  987+377+144+55+21+8+3+1;
2206 = 1597+377+144+55+21+8+3+1;
2439 = 1597+610+144+55+21+8+3+1;
2528 = 1597+610+233+55+21+8+3+1;
2562 = 1597+610+233+89+21+8+3+1.
		

Links

• Reinhard Zumkeller, Table of n, a(n) for n = 1..10000

Crossrefs

Cf. A035517, A007895, A179242, A179243, A179244, A179245, A179246, A179247, A179249, A179250, A179251, A179252, A179253.

Programs

Haskell

a179249 n = a179249_list !! (n-1)
a179249_list = filter ((== 9) . a007895) [1..]
-- Reinhard Zumkeller, Mar 10 2013

Maple

with(combinat): B := proc (n) local A, ct, m, j: A := proc (n) local i: for i while fibonacci(i) <= n do n-fibonacci(i) end do end proc: ct := 0: m := n: for j while 0 < A(m) do ct := ct+1: m := A(m) end do: ct+1 end proc: Q := {}: for i from fibonacci(17)-1 to 5000 do if B(i) = 8 then Q := `union`(Q, {i}) else end if end do: Q;

Mathematica

zeck = DigitCount[Select[Range[10^5], BitAnd[#, 2*#] == 0 &], 2, 1];
Position[zeck, 8] // Flatten (* Jean-François Alcover, Jan 30 2018 *)