A179251 Numbers that have 11 terms in their Zeckendorf representation.

28656, 39602, 43783, 45380, 45990, 46223, 46312, 46346, 46359, 46364, 46366, 46367, 57313, 61494, 63091, 63701, 63934, 64023, 64057, 64070, 64075, 64077, 64078, 68259, 69856, 70466, 70699, 70788, 70822, 70835, 70840, 70842, 70843

Offset: 1

Author

Emeric Deutsch, Jul 05 2010

Keywords

• nonn

Comments

A007895(a(n)) = 11. - Reinhard Zumkeller, Mar 10 2013

Examples

			28656=17711+6765+2584+987+377+144+55+21+8+3+1;
39602=28657+6765+2584+987+377+144+55+21+8+3+1;
		

Links

• Reinhard Zumkeller, Table of n, a(n) for n = 1..10000

Crossrefs

Cf. A035517, A007895, A179242, A179243, A179244, A179245, A179246, A179247, A179248, A179249, A179250, A179252, A179253.

Programs

Haskell

a179251 n = a179251_list !! (n-1)
a179251_list = filter ((== 11) . a007895) [1..]
-- Reinhard Zumkeller, Mar 10 2013

Maple

with(combinat): B := proc (n) local A, ct, m, j: A := proc (n) local i: for i while fibonacci(i) <= n do n-fibonacci(i) end do end proc: ct := 0: m := n: for j while 0 < A(m) do ct := ct+1: m := A(m) end do: ct+1 end proc: Q := {}: for i from fibonacci(23)-1 to 73000 do if B(i) = 11 then Q := `union`(Q, {i}) else end if end do: Q;

Mathematica

Select[Range[6*10^6], BitAnd[#, 2*#] == 0&] // DigitCount[#, 2, 1]& // Position[#, 11]& // Flatten (* Jean-François Alcover, Feb 15 2018 *)