cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A182073 Square array read by antidiagonals: T(n,k) = n!*k! / (floor(n/2)! * floor(k/2)! * floor((n+k)/2)!).

Original entry on oeis.org

1, 1, 1, 2, 1, 2, 6, 2, 2, 6, 6, 3, 2, 3, 6, 30, 6, 6, 6, 6, 30, 20, 10, 4, 6, 4, 10, 20, 140, 20, 20, 12, 12, 20, 20, 140, 70, 35, 10, 15, 6, 15, 10, 35, 70, 630, 70, 70, 30, 30, 30, 30, 70, 70, 630, 252, 126, 28, 42, 12, 30, 12, 42, 28, 126, 252
Offset: 0

Views

Author

Peter Bala, Apr 10 2012

Keywords

Comments

Compare with A068555 whose entries are given by (2*n)!*(2*k)!/(n!*k!*(n+k)!). See also A211226.

Examples

			As a square array
.n\k.|...0....1....2....3....4....5....6...
= = = = = = = = = = = = = = = = = = = = = =
..0..|...1....1....2....6....6...30...20...
..1..|...1....1....2....3....6...10...20...
..2..|...2....2....2....6....4...20...10...
..3..|...6....3....6....6...12...15...30...
..4..|...6....6....4...12....6...30...12...
..5..|..30...10...20...15...30...30...60...
..6..|..20...20...10...30...12...60...20...
...
Formatted as a triangle
.n\k.|...0....1....2....3....4....5....6
= = = = = = = = = = = = = = = = = = = = =
..0..|...1
..1..|...1....1
..2..|...2....1....2
..3..|...6....2....2....6
..4..|...6....3....2....3....6
..5..|..30....6....6....6....6...30
..6..|..20...10....4....6....4...10...20
...
		

Crossrefs

Programs

  • Mathematica
    T[n_, k_] := n!*k!/(Floor[n/2]!*Floor[k/2]!*Floor[(n + k)/2]!);
    TableForm[Table[T[n, k], {n, 0, 5}, {k, 0, 10}]]
    Table[T[n - k, k], {n, 0, 10}, {k, n, 0, -1}] // Flatten (* G. C. Greubel, Aug 20 2017 *)

Formula

That T(n,k) is an integer follows from the formulas:
T(2*n,2*k) = (2*n)!*(2*k)!/(n!*k!*(n+k)!) = A068555(n,k);
T(2*n,2*k+1) = (2*n)!*(2*k+1)!/(n!*k!*(n+k)!) = (2*k+1)*A068555(n,k);
T(2*n+1,2*k) = (2*n+1)!*(2*k)!/(n!*k!*(n+k)!) = (2*n+1)*A068555(n,k);
T(2*n+1,2*k+1) = (2*n+1)!*(2*k+1)!/(n!*k!*(n+k+1)!) = (2*k+1)*A135573(n,k).