cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A183712 1/20 of the number of (n+1) X 3 0..4 arrays with every 2 X 2 subblock strictly increasing clockwise or counterclockwise with one decrease.

Original entry on oeis.org

5, 17, 54, 174, 559, 1797, 5776, 18566, 59677, 191821, 616574, 1981866, 6370351, 20476345, 65817520, 211558554, 680016837, 2185791545, 7025832918, 22583273462, 72589861759, 233327025821, 749987665760, 2410700161342, 7748761123965, 24906995867477
Offset: 1

Views

Author

R. H. Hardin, Jan 06 2011

Keywords

Comments

Column 2 of A183719. [Corrected by M. F. Hasler, Oct 07 2014]
This sequence counts closed walks of length (n+2) at the vertex of a triangle, to which a loop has been added to one of the remaining vertices and two loops has been added to the third vertex. - David Neil McGrath, Sep 04 2014
From Greg Dresden, Mar 02 2025: (Start)
a(n) is the number of ways to tile, with squares and dominoes, a 2 X n board with two extra spaces at the end. Here is the board for n=3:
|||_|
|||_|||,
and here is one of the a(3)=54 possible tilings of this board:
|_| |_
|||_|_|.
Compare to A033505 (tilings of 2 X n board with one extra space at the end) and A030186 (tilings of 2 X n board with no extra spaces at the end). (End)

Examples

			Some solutions for 5 X 3:
..0..1..4....1..2..0....4..0..4....4..3..4....4..0..4....1..4..0....3..4..2
..3..2..3....0..3..4....2..1..3....0..2..0....3..2..3....2..3..1....1..0..1
..4..1..0....1..2..1....4..0..4....4..3..4....0..1..0....0..4..0....2..4..3
..3..2..3....0..3..4....3..2..3....0..2..1....4..2..3....1..3..1....1..0..1
..4..0..4....1..2..1....4..1..0....4..3..0....0..1..0....0..4..0....2..3..2
...
...R..L.......R..L.......R..L.......L..R.......R..L.......L..R.......R..L...
...L..R.......L..R.......L..R.......R..L.......L..R.......R..L.......L..R...
...R..L.......R..L.......R..L.......L..R.......R..L.......L..R.......R..L...
...L..R.......L..R.......L..R.......R..L.......L..R.......R..L.......L..R...
		

Crossrefs

Programs

Formula

a(n) = 3*a(n-1) + a(n-2) - a(n-3).
The top left element of A^(n+2) where A=(0,1,1;1,1,1;1,1,2). - David Neil McGrath, Sep 04 2014
a(n) ~ c*k^n where k = 1.629316... is the largest root of x^3 - 3x^2 - x + 1 and c = 1.6293... is conjecturally the largest root of 148x^3 - 296x^2 + 90x - 1. - Charles R Greathouse IV, Sep 15 2014
G.f.: x*(5+2*x-2*x^2) / (1-3*x-x^2+x^3). - Colin Barker, Mar 16 2016
a(n) = A030186(n) + A033505(n). - Greg Dresden, Mar 02 2025
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