cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A188725 Decimal expansion of shape of a (2*Pi)-extension rectangle; shape = Pi + sqrt(1 + Pi^2).

Original entry on oeis.org

6, 4, 3, 8, 5, 0, 0, 9, 6, 3, 0, 6, 5, 4, 0, 8, 3, 9, 7, 2, 2, 3, 2, 3, 2, 5, 6, 3, 5, 9, 4, 6, 9, 1, 7, 2, 9, 2, 6, 2, 1, 6, 6, 5, 4, 0, 8, 1, 3, 2, 6, 1, 5, 2, 5, 6, 1, 0, 6, 5, 1, 7, 3, 2, 5, 8, 9, 5, 9, 2, 1, 2, 6, 3, 3, 4, 3, 7, 5, 1, 1, 6, 9, 3, 8, 6, 9, 6, 6, 9, 2, 7, 7, 2, 1, 5, 3, 0, 9, 8, 5, 0, 0, 3, 9, 3, 0, 2, 8, 1, 2, 1, 5, 8, 5, 8, 7, 0, 2, 3, 1, 6, 7, 6, 5, 3, 0, 9, 1, 5
Offset: 1

Views

Author

Clark Kimberling, Apr 09 2011

Keywords

Comments

See A188640 for definitions of shape and r-extension rectangle. Briefly, an r-extension rectangle is composed of two rectangles of shape r.
A 2*Pi-extension rectangle matches the continued fraction [6,2,3,1,1,3,2,1,16,47,...] of the shape L/W = Pi + sqrt(1 + Pi^2). This is analogous to the matching of a golden rectangle to the continued fraction [1,1,1,1,1,1,1,...]. Specifically, for the (2*Pi)-extension rectangle, 6 squares are removed first, then 2 squares, then 3 squares, then 1 square, then 1 square, ..., so that the original rectangle is partitioned into an infinite collection of squares.

Examples

			6.4385009630654083972232325635946917292621665408132615256106...
		

Crossrefs

Programs

  • Magma
    SetDefaultRealField(RealField(100)); R:= RealField(); Pi(R) + Sqrt(1 + Pi(R)^2); // G. C. Greubel, Oct 31 2018
  • Maple
    evalf(Pi+sqrt(1+Pi^2),140); # Muniru A Asiru, Nov 01 2018
  • Mathematica
    r = 2*Pi; t = (r + (4 + r^2)^(1/2))/2; FullSimplify[t]
    N[t, 130]
    RealDigits[N[t, 130]][[1]] (* A188725 *)
    ContinuedFraction[t, 120] (* A188726 *)
    RealDigits[Pi + Sqrt[1 + Pi^2], 10, 100][[1]] (* G. C. Greubel, Oct 31 2018 *)
  • PARI
    default(realprecision, 100); Pi + sqrt(1 + Pi^2) \\ G. C. Greubel, Oct 31 2018