A191816 Continued fraction of the number A191504 = 1/(1+1/(1+2/(1+3/(1+5/(1+7/(1+11/(...))))))), where the numerators > 1 are the primes.

0, 1, 1, 1, 23, 1, 1, 1, 2, 1, 2, 3, 5, 2, 1, 30, 18, 1, 2, 1, 2, 4, 2, 399, 2, 2, 3, 1, 2, 1, 4, 1, 1, 4, 2, 1, 2, 2, 12, 1, 3, 1, 3, 1, 2, 6, 1, 1, 1, 43, 1, 1, 1, 4, 1, 1, 16, 16, 1, 8, 1, 3, 3, 7, 1, 4, 25, 1, 4, 1, 1, 4

Offset: 0

Author

M. F. Hasler, Jun 17 2011

Keywords

• nonn
• cofr

Comments

The subsequence starting with the third (resp. second) term represents the continued fraction of the number A191815 = 1+2/(1+3/(1+5/(1+7/(1+11/(...))))) (resp. of 1+1/A191815).

Crossrefs

Cf. A191504 (decimal expansion), A191815.

Extensions

Offset changed by Andrew Howroyd, Jul 03 2024