A203025 Largest perfect power divisor of n.
1, 1, 1, 4, 1, 1, 1, 8, 9, 1, 1, 4, 1, 1, 1, 16, 1, 9, 1, 4, 1, 1, 1, 8, 25, 1, 27, 4, 1, 1, 1, 32, 1, 1, 1, 36, 1, 1, 1, 8, 1, 1, 1, 4, 9, 1, 1, 16, 49, 25, 1, 4, 1, 27, 1, 8, 1, 1, 1, 4, 1, 1, 9, 64, 1, 1, 1, 4, 1, 1, 1, 36, 1, 1, 25, 4, 1, 1, 1, 16, 81, 1
Offset: 1
Keywords
Examples
a(40)=a(2^3*5)=2^3=8.
Links
- Giovanni Resta, Table of n, a(n) for n = 1..10000
Programs
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Maple
A203025:=proc(n) local a,Le,d,i,k,pe; pe := ifactors(n)[2]; Le := {seq(i[2],i=pe)} minus {1}; a := 1; for k in Le do d := mul(i[1]^(k*floor(i[2]/k)), i=pe) ; a:=max(a,d); end do; a end proc: seq(A203025(n),n=1..10000); # Felix Huber, Jun 01 2025
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Mathematica
Table[If[SquareFreeQ[n], 1, s = FactorInteger[n]; Max[Table[Times @@ Cases[s, {p_, ep_} :> p^i /; (ep >= i)], {i, 2, Max[s[[All, 2]]]}]]], {n, 100}] (* Olivier Gerard, Jun 03 2016 *)
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PARI
a(n)=my(f=factor(n),mx=1);for(e=2,if(n>1,vecmax(f[,2])), mx=max(mx,prod(i=1,#f[,1],f[i,1]^(f[i,2]\e*e))));mx \\ Charles R Greathouse IV, Dec 28 2011
Formula
Extensions
Values matching definition restored by Franklin T. Adams-Watters, Jun 06 2016
Comments