A210358 Minimum value in the inverse of Hilbert's matrix.

1, -6, -180, -4200, -117600, -3969000, -115259760, -3030051024, -106051785840, -3363975014400, -98227319533200, -3110531785218000, -103492384705710000, -3211851661880141280, -96355549856404238400, -3303308595002047632000, -106681852579497947388000

Offset: 1

Author

T. D. Noe, Apr 02 2012

Keywords

• sign

Links

• T. D. Noe, Table of n, a(n) for n = 1..100

Crossrefs

Cf. A061065, A189765 (inverse matrix), A210357.

Programs

Mathematica

Table[im = Inverse[HilbertMatrix[n]]; Min[Flatten[im]], {n, 20}]

PARI

a(n)=vecmin(1/mathilbert(n)) \\ Hugo Pfoertner, Feb 11 2020