cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A211216 Expansion of (1-8*x+21*x^2-20*x^3+5*x^4)/(1-9*x+28*x^2-35*x^3+15*x^4-x^5).

Original entry on oeis.org

1, 1, 2, 5, 14, 42, 132, 429, 1430, 4862, 16795, 58766, 207783, 740924, 2660139, 9603089, 34818270, 126676726, 462125928, 1689438278, 6186432967, 22682699779, 83249302471, 305773834030, 1123771473120, 4131947428007, 15197952958467, 55915691993228
Offset: 0

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Author

Bruno Berselli, May 11 2012

Keywords

Comments

In the paper of Kitaev, Remmel and Tiefenbruck (see the Links section), Q_(132)^(k,0,0,0)(x,0) represents a generating function depending on k and x.
For successive values of k we have:
k=1, the g.f. of A000012: 1/(1-x);
k=2, " A011782: (1-x)/(1-2*x);
k=3, " A001519: (1-2*x)/(1-3*x+x^2);
k=4, " A124302: (1-3*x+x^2)/(1-4*x+3*x^2);
k=5, " A080937: (1-4*x+3*x^2)/(1-5*x+6*x^2-x^3);
k=6, " A024175: (1-5*x+6*x^2-x^3)/(1-6*x+10*x^2-4*x^3);
k=7, " A080938: (1-6*x+10*x^2-4*x^3)/(1-7*x+15*x^2-10*x^3+x^4);
k=8, " A033191: (1-7*x+15*x^2-10*x^3+x^4)/(1-8*x+21*x^2
-20*x^3+5*x^4).
This sequence corresponds to the case k=9.
We observe that the coefficients of numerators and denominators are in A115139.
In general, Q_(132)^(k,0,0,0)(x,0) is the generating function for Dyck paths whose maximum height is less than or equal to k; also, it is the generating function of rooted binary trees T which have no nodes 'eta' such that there are >= k left edges on the path from 'eta' to the root of T (see cited paper, page 11).

Crossrefs

Programs

  • Magma
    m:=28; R:=PowerSeriesRing(Integers(), m); Coefficients(R!((1-8*x+21*x^2-20*x^3+5*x^4)/(1-9*x+28*x^2-35*x^3+15*x^4-x^5)));
  • Mathematica
    CoefficientList[Series[(1 - 8 x + 21 x^2 - 20 x^3 + 5 x^4)/(1 - 9 x + 28 x^2 - 35 x^3 + 15 x^4 - x^5), {x, 0, 27}], x]
  • PARI
    Vec((1-8*x+21*x^2-20*x^3+5*x^4)/(1-9*x+28*x^2-35*x^3+15*x^4-x^5)+O(x^28))
    

Formula

G.f.: (1-3*x+x^2)*(1-5*x+5*x^2)/(1-9*x+28*x^2-35*x^3+15*x^4-x^5).
G.f.: 1/(1-x/(1-x/(1-x/(1-x/(1-x/(1-x/(1-x/(1-x/(1-x))))))))). - Philippe Deléham, Mar 14 2013
a(n) = A000108(n) + Sum_{k=1..n} (4*binomial(2*n, n+11*k) - binomial(2*n+2, n+11*k+1)). - Greg Dresden, Jan 28 2023