A213759 Principal diagonal of the convolution array A213783.
1, 4, 11, 22, 39, 62, 93, 132, 181, 240, 311, 394, 491, 602, 729, 872, 1033, 1212, 1411, 1630, 1871, 2134, 2421, 2732, 3069, 3432, 3823, 4242, 4691, 5170, 5681, 6224, 6801, 7412, 8059, 8742, 9463, 10222, 11021, 11860, 12741, 13664, 14631
Offset: 1
Links
- Clark Kimberling, Table of n, a(n) for n = 1..1000
- Index entries for linear recurrences with constant coefficients, signature (3,-2,-2,3,-1).
Crossrefs
Partial sums of A047838. - Guenther Schrack, May 24 2018
Programs
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Mathematica
b[n_] := Floor[(n + 2)/2]; c[n_] := Floor[(n + 1)/2]; t[n_, k_] := Sum[b[k - i] c[n + i], {i, 0, k - 1}] TableForm[Table[t[n, k], {n, 1, 10}, {k, 1, 10}]] Flatten[Table[t[n - k + 1, k], {n, 12}, {k, n, 1, -1}]] r[n_] := Table[t[n, k], {k, 1, 60}] (* A213783 *) Table[t[n, n], {n, 1, 40}] (* A213759 *) LinearRecurrence[{3,-2,-2,3,-1},{1,4,11,22,39},50] (* Harvey P. Dale, Jul 22 2014 *)
Formula
a(n) = (3 - 3*(-1)^n - 4*n + 18*n^2 + 4*n^3)/24.
a(n) = 3*a(n-1) - 2*a(n-2) - 2*a(n-3) + 3*a(n-4) - a(n-5).
G.f.: x*(1 + x + x^2 - x^3)/((1 - x)^4 *(1 + x)).
a(n+1) = a(n) + A047838(n+2) for n > 0. - Guenther Schrack, May 24 2018
a(n) = A212964(n+2) - n for n > 0. - Guenther Schrack, May 30 2018