cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A219529 Coordination sequence for 3.3.4.3.4 Archimedean tiling.

Original entry on oeis.org

1, 5, 11, 16, 21, 27, 32, 37, 43, 48, 53, 59, 64, 69, 75, 80, 85, 91, 96, 101, 107, 112, 117, 123, 128, 133, 139, 144, 149, 155, 160, 165, 171, 176, 181, 187, 192, 197, 203, 208, 213, 219, 224, 229, 235, 240, 245, 251, 256, 261, 267, 272, 277, 283, 288, 293, 299
Offset: 0

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Author

Allan C. Wechsler, Nov 21 2012

Keywords

Comments

a(n) is the number of vertices of the 3.3.4.3.4 tiling (which has three triangles and two squares, in the given cyclic order, meeting at each vertex) whose shortest path connecting them to a given origin vertex contains n edges.
This is the dual tiling to the Cairo tiling (cf. A296368). - N. J. A. Sloane, Nov 02 2018
First few terms provided by Allan C. Wechsler; Fred Lunnon and Fred Helenius gave the next few; Fred Lunnon suggested that the recurrence was a(n+3) = a(n) + 16 for n > 1. [This conjecture is true - see the CGS-NJAS link for a proof. - N. J. A. Sloane, Dec 31 2017]
Appears also to be coordination sequence for node of type V2 in "krd" 2-D tiling (or net). This should be easy to prove by the coloring book method (see link). - N. J. A. Sloane, Mar 25 2018
Appears also to be coordination sequence for node of type V1 in "krj" 2-D tiling (or net). This also should be easy to prove by the coloring book method (see link). - N. J. A. Sloane, Mar 26 2018
First differences of A301696. - Klaus Purath, May 23 2020

References

  • Branko Grünbaum and G. C. Shephard, Tilings and Patterns. W. H. Freeman, New York, 1987. See Table 2.2.1, page 67, 1st row, 2nd tiling, also 2nd row, third tiling.

Crossrefs

List of coordination sequences for uniform planar nets: A008458 (the planar net 3.3.3.3.3.3), A008486 (6^3), A008574 (4.4.4.4 and 3.4.6.4), A008576 (4.8.8), A008579 (3.6.3.6), A008706 (3.3.3.4.4), A072154 (4.6.12), A219529 (3.3.4.3.4), A250120 (3.3.3.3.6), A250122 (3.12.12).
Coordination sequences for the 20 2-uniform tilings in the order in which they appear in the Galebach catalog, together with their names in the RCSR database (two sequences per tiling): #1 krt A265035, A265036; #2 cph A301287, A301289; #3 krm A301291, A301293; #4 krl A301298, A298024; #5 krq A301299, A301301; #6 krs A301674, A301676; #7 krr A301670, A301672; #8 krk A301291, A301293; #9 krn A301678, A301680; #10 krg A301682, A301684; #11 bew A008574, A296910; #12 krh A301686, A301688; #13 krf A301690, A301692; #14 krd A301694, A219529; #15 krc A301708, A301710; #16 usm A301712, A301714; #17 krj A219529, A301697; #18 kre A301716, A301718; #19 krb A301720, A301722; #20 kra A301724, A301726.

Programs

  • Haskell
    -- Very slow, could certainly be accelerated.  SST stands for Snub Square Tiling.
    setUnion [] l2 = l2
    setUnion (a:rst) l2 = if (elem a l2) then doRest else (a:doRest)
      where doRest = setUnion rst l2
    setDifference [] l2 = []
    setDifference (a:rst) l2 = if (elem a l2) then doRest else (a:doRest)
      where doRest = setDifference rst l2
    adjust k = (if (even k) then 1 else -1)
    weirdAdjacent (x,y) = (x+(adjust y),y+(adjust x))
    sstAdjacents (x,y) = [(x+1,y),(x-1,y),(x,y+1),(x,y-1),(weirdAdjacent (x,y))]
    sstNeighbors core = foldl setUnion core (map sstAdjacents core)
    sstGlob n core = if (n == 0) then core else (sstGlob (n-1) (sstNeighbors core))
    sstHalo core = setDifference (sstNeighbors core) core
    origin = [(0,0)]
    a219529 n = length (sstHalo (sstGlob (n-1) origin))
    -- Allan C. Wechsler, Nov 30 2012
    
  • Maple
    A219529:= n -> `if`(n=0, 1, (16*n +1 - `mod`(n+1,3))/3);
    seq(A219529(n), n = 0..60); # G. C. Greubel, May 27 2020
  • Mathematica
    Join[{1}, LinearRecurrence[{1,0,1,-1}, {5,11,16,21}, 60]] (* Jean-François Alcover, Dec 13 2018 *)
    Table[If[n==0, 1, (16*n +1 - Mod[n+1, 3])/3], {n, 0, 60}] (* G. C. Greubel, May 27 2020 *)
    CoefficientList[Series[(x+1)^4/((x^2+x+1)(x-1)^2),{x,0,70}],x] (* Harvey P. Dale, Jul 03 2021 *)
  • Sage
    [1]+[(16*n+1 -(n+1)%3)/3 for n in (1..60)] # G. C. Greubel, May 27 2020

Formula

Conjectured to be a(n) = floor((16n+1)/3) for n>0; a(0) = 1; this is a consequence of the suggested recurrence due to Lunnon (see comments). [This conjecture is true - see the CGS-NJAS link in A296368 for a proof. - N. J. A. Sloane, Dec 31 2017]
G.f.: (x+1)^4/((x^2+x+1)*(x-1)^2). - N. J. A. Sloane, Feb 07 2018
From G. C. Greubel, May 27 2020: (Start)
a(n) = (16*n - ChebyshevU(n-1, -1/2))/3 for n>0 with a(0)=1.
a(n) = (A008598(n) - A049347(n-1))/3 for n >0 with a(0)=1. (End)

Extensions

Corrected attributions and epistemological status in Comments; provided slow Haskell code - Allan C. Wechsler, Nov 30 2012
Extended by Joseph Myers, Dec 04 2014