A221530 Triangle read by rows: T(n,k) = A000005(k)*A000041(n-k).
1, 1, 2, 2, 2, 2, 3, 4, 2, 3, 5, 6, 4, 3, 2, 7, 10, 6, 6, 2, 4, 11, 14, 10, 9, 4, 4, 2, 15, 22, 14, 15, 6, 8, 2, 4, 22, 30, 22, 21, 10, 12, 4, 4, 3, 30, 44, 30, 33, 14, 20, 6, 8, 3, 4, 42, 60, 44, 45, 22, 28, 10, 12, 6, 4, 2, 56, 84, 60, 66, 30, 44, 14, 20, 9, 8, 2, 6
Offset: 1
Examples
For n = 6: ------------------------- k A000005 T(6,k) 1 1 * 7 = 7 2 2 * 5 = 10 3 2 * 3 = 6 4 3 * 2 = 6 5 2 * 1 = 2 6 4 * 1 = 4 . A000041 ------------------------- So row 6 is [7, 10, 6, 6, 4, 2]. Note that the sum of row 6 is 7+10+6+6+2+4 = 35 equals A006128(6). . Triangle begins: 1; 1, 2; 2, 2, 2; 3, 4, 2, 3; 5, 6, 4, 3, 2; 7, 10, 6, 6, 2, 4; 11, 14, 10, 9, 4, 4, 2; 15, 22, 14, 15, 6, 8, 2, 4; 22, 30, 22, 21, 10, 12, 4, 4, 3; 30, 44, 30, 33, 14, 20, 6, 8, 3, 4; 42, 60, 44, 45, 22, 28, 10, 12, 6, 4, 2; 56, 84, 60, 66, 30, 44, 14, 20, 9, 8, 2, 6; ...
Links
- Paolo Xausa, Table of n, a(n) for n = 1..11325 (rows 1..150 of the triangle, flattened)
Crossrefs
Programs
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Mathematica
A221530row[n_]:=DivisorSigma[0,Range[n]]PartitionsP[n-Range[n]];Array[A221530row,10] (* Paolo Xausa, Sep 04 2023 *)
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PARI
row(n) = vector(n, i, numdiv(i)*numbpart(n-i)); \\ Michel Marcus, Jul 18 2014
Comments