A229141 Number of circular permutations i_1, ..., i_n of 1, ..., n such that all the n sums i_1^2+i_2, ..., i_{n-1}^2+i_n, i_n^2+i_1 are among those integers m with the Jacobi symbol (m/(2n+1)) equal to 1.
1, 0, 0, 2, 0, 1, 0, 5, 35, 0
Offset: 1
Examples
a(4) = 2 due to the permutations (1,3,2,4) and (1,4,3,2). a(6) = 1 due to the permutation (1,3,5,2,6,4). a(8) = 5 due to the permutations (1,3,4,2,5,8,6,7), (1,8,3,6,2,4,5,7), (1,8,3,6,7,4,2,5), (1,8,3,7,6,2,4,5), (1,8,6,7,3,4,2,5). a(9) > 0 due to the permutation (1,3,7,6,8,4,9,2,5).
Links
- Zhi-Wei Sun, Some new problems in additive combinatorics, preprint, arXiv:1309.1679 [math.NT], 2013-2014.
Programs
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Mathematica
(* A program to compute the desired circular permutations for n = 8. *) f[i_,j_,p_]:=f[i,j,p]=JacobiSymbol[i^2+j,p]==1 V[i_]:=Part[Permutations[{2,3,4,5,6,7,8}],i] m=0 Do[Do[If[f[If[j==0,1,Part[V[i],j]],If[j<7,Part[V[i],j+1],1],17]==False,Goto[aa]],{j,0,7}]; m=m+1;Print[m,":"," ",1," ",Part[V[i],1]," ",Part[V[i],2]," ",Part[V[i],3]," ",Part[V[i],4]," ",Part[V[i],5]," ",Part[V[i],6]," ",Part[V[i],7]];Label[aa];Continue,{i,1,7!}]
Extensions
a(10) = 0 from R. J. Mathar, Sep 15 2013
Comments