A231014 Number of months after which it is not possible to have the same calendar for the entire month with the same number of days, in the Julian calendar.

1, 2, 4, 5, 7, 10, 11, 12, 13, 16, 19, 21, 24, 25, 27, 28, 30, 33, 36, 39, 41, 42, 44, 45, 47, 48, 49, 50, 51, 53, 56, 58, 59, 61, 62, 65, 66, 67, 70, 71, 73, 74, 76, 79, 82, 83, 84, 85, 87, 88, 90, 91, 93, 96, 97, 99, 100, 102, 104, 105, 107, 108, 111, 113, 116, 119, 120

Offset: 1

Author

Aswini Vaidyanathan, Nov 02 2013

Keywords

• nonn
• easy

Comments

In the Julian calendar, a year is a leap year if and only if it is a multiple of 4 and all century years are leap years.

Assuming this fact, this sequence is periodic with a period of 336.

This is the complement of A231011.

Links

• Time And Date, Repeating Months
• Time And Date, Julian Calendar

Crossrefs

Cf. A230995-A231014.

Cf. A231009 (Gregorian calendar).

Programs

PARI

m=[0,3,3,6,1,4,6,2,5,0,3,5];n=[31,28,31,30,31,30,31,31,30,31,30,31];y=vector(336,i,(m[((i-1)%12)+1]+((5*((i-1)\48)+(((i-1)\12)%4)-!((i-1)%48)-!((i-2)%48))))%7);x=vector(336,i,n[((i-1)%12)+1]+!((i-2)%48));for(p=0,336,j=0;for(q=0,336,if(y[(q%336)+1]==y[((q+p)%336)+1]&&x[(q%336)+1]==x[((q+p)%336)+1],j=1;break));if(j==0,print1(p", ")))