cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A231985 Decimal expansion of the side length (in degrees) of the spherical square whose solid angle is exactly one deg^2.

Original entry on oeis.org

1, 0, 0, 0, 0, 1, 2, 6, 9, 2, 3, 4, 4, 1, 6, 3, 3, 7, 9, 1, 6, 0, 6, 0, 3, 6, 3, 3, 3, 5, 8, 6, 6, 1, 7, 7, 8, 6, 3, 9, 6, 5, 2, 1, 8, 5, 2, 8, 7, 7, 6, 6, 6, 4, 9, 0, 3, 5, 0, 7, 8, 1, 3, 6, 4, 3, 8, 2, 8, 4, 3, 2, 4, 1, 8, 9, 7, 4, 7, 5, 1, 7, 2, 2, 4, 0, 2, 4, 1, 2, 1, 1, 9, 0, 2, 4, 6, 7, 9, 8, 8, 5, 9, 2, 0
Offset: 1

Views

Author

Stanislav Sykora, Nov 17 2013

Keywords

Comments

This answers the inverse problem of A231984 (not to be confused with its inverse value): what is the side arc-length of a spherical square required to subtend exactly 1 deg^2. Since the solid angle of a spherical square with side s (in rads) is Omega = 4*arcsin(sin(s/2)^2) (in sr), we have s = 2*arcsin(sqrt(Omega/4)). Converting Omega = 1 deg^2 into steradians (A231982), applying the formula, and converting the result from radians to degrees (A072097), one obtains the result.

Examples

			1.0000126923441633791606036333586617786396521852877666490350781364...
		

References

  • G. V. Brummelen, Heavenly Mathematics: The Forgotten Art of Spherical Trigonometry, Princeton University Press, 2012, ISBN 978-0691148922.

Crossrefs

Cf. A000796 (Pi), A072097 (rad/deg), A019685 (deg/rad), A231981 (sr/deg^2), A231982 (deg^2/sr), A231983, A231984 (inverse problem), A231986, A231985, A231987 (same problem for 1sr).

Programs

  • Mathematica
    RealDigits[(360/Pi)*ArcSin[Sqrt[Sin[(Pi/360)^2]]],10,120][[1]] (* Harvey P. Dale, Jun 09 2021 *)
  • PARI
    default(realprecision, 120);
    (360/Pi)*asin(sqrt(sin((Pi/360)^2))) \\ or
    (180/Pi)*solve(x = 0, 1, 4*asin(sin(x/2)^2) - (Pi/180)^2) \\ Rick L. Shepherd, Jan 29 2014

Formula

(360/Pi)*arcsin(sqrt(sin((Pi/360)^2))).