A234605 a(n+1) is next smallest cube ending with a(n), initial term is 0.
0, 1000, 1331000, 1003303631331000, 1000000003003300003006603631003303631331000
Offset: 1
Programs
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Mathematica
a[n_]:=(Sum[10^((3^i+1)/2),{i,0,n-1}])^3; Array[a,5,0] (* Stefano Spezia, Mar 07 2025 *)
Formula
a(n) = (Sum_{i=0..n-1} 10^((3^i+1)/2))^3. - Max Alekseyev, Jan 07 2015
Comments