cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-4 of 4 results.

A235596 Second column of triangle in A235595.

Original entry on oeis.org

0, 0, 2, 9, 40, 195, 1056, 6321, 41392, 293607, 2237920, 18210093, 157329096, 1436630091, 13810863808, 139305550065, 1469959371232, 16184586405327, 185504221191744, 2208841954063317, 27272621155678840, 348586218389733555, 4605223387997411872, 62797451641106266329, 882730631284319415504
Offset: 1

Views

Author

N. J. A. Sloane, Jan 15 2014

Keywords

Examples

			G.f. = 2*x^3 + 9*x^4 + 40*x^5 + 195*x^6 + 1056*x^7 + 6321*x^8 + 41392*x^9 + ...
		

Crossrefs

Programs

  • Mathematica
    gf[k_] := gf[k] = If[k == 0, x, x*E^gf[k-1]]; a[n_, k_] := n!*Coefficient[Series[gf[k], {x, 0, n+1}], x, n]; a[n_] := (a[n, 2] - a[n, 1])/n; Array[a, 25] (* Jean-François Alcover, Mar 18 2014, after Alois P. Heinz *)
    Table[Sum[BellY[n - 1, k, Range[n - 1]], {k, 0, n - 2}], {n, 1, 25}] (* Vladimir Reshetnikov, Nov 09 2016 *)
  • Python
    from sympy import binomial
    from sympy.core.cache import cacheit
    @cacheit
    def b(n, h): return 1 if min(n, h)==0 else sum([binomial(n - 1, j - 1)*j*b(j - 1, h - 1)*b(n - j, h) for j in range(1, n + 1)])
    def a(n): return b(n - 1, 1) - b(n - 1, 0)
    print([a(n) for n in range(1, 31)]) # Indranil Ghosh, Aug 26 2017

Formula

a(n) = A000248(n-1) - 1. - Alois P. Heinz, Jun 21 2019

A234953 Normalized total height of all rooted trees on n labeled nodes.

Original entry on oeis.org

0, 1, 5, 37, 357, 4351, 64243, 1115899, 22316409, 505378207, 12789077631, 357769603027, 10965667062133, 365497351868767, 13163965052815515, 509522144541045811, 21093278144993719665, 930067462093579181119, 43518024090910884374263, 2153670733766937656155699
Offset: 1

Views

Author

N. J. A. Sloane, Jan 14 2014

Keywords

Comments

Equals A001854(n)/n. That is, similar to A001854, except here the root always has the fixed label 1.
This was in one of my thesis notebooks from 1964 (see the scans in A000435), but because it wasn't of central importance it was never added to the OEIS.

Crossrefs

Programs

  • Mathematica
    gf[k_] := gf[k] = If[k == 0, x, x*E^gf[k-1]]; a[n_, k_] := n!*Coefficient[Series[gf[k], {x, 0, n+1}], x, n]; a[n_] := Sum[k*(a[n, k] - a[n, k-1]), {k, 1, n-1}]/n; Array[a, 20] (* Jean-François Alcover, Mar 18 2014, after Alois P. Heinz *)
  • Python
    from sympy import binomial
    from sympy.core.cache import cacheit
    @cacheit
    def b(n, h): return 1 if min(n, h)==0 else sum([binomial(n - 1, j - 1)*j*b(j - 1, h - 1)*b(n - j, h) for j in range(1, n + 1)])
    def T(n, k): return b(n - 1, k - 1) - b(n - 1, k - 2)
    def a(n): return sum([k*T(n, k) for k in range(1, n)])
    print([a(n) for n in range(1, 31)]) # Indranil Ghosh, Aug 26 2017

Formula

a(n) = Sum_{k=1..n-1} k*A034855(n,k)/n = Sum_{k=1..n-1} k*A235595(n,k).

A236396 Triangle read by rows: T(n,k) = number of rooted labeled trees with n nodes and height <= k, for n >= 1, 0 <= k <= n-1.

Original entry on oeis.org

1, 0, 2, 0, 3, 9, 0, 4, 40, 64, 0, 5, 205, 505, 625, 0, 6, 1176, 4536, 7056, 7776, 0, 7, 7399, 46249, 89929, 112609, 117649, 0, 8, 50576, 526352, 1284032, 1835072, 2056832, 2097152, 0, 9, 372537, 6604497, 20351601, 33188481, 40325121, 42683841, 43046721
Offset: 1

Views

Author

N. J. A. Sloane, Jan 28 2014

Keywords

Comments

If we replace each row by its differences we get A034855.

Examples

			Triangle begins:
[1],
[0, 2],
[0, 3, 9],
[0, 4, 40, 64],
[0, 5, 205, 505, 625],
[0, 6, 1176, 4536, 7056, 7776],
[0, 7, 7399, 46249, 89929, 112609, 117649],
[0, 8, 50576, 526352, 1284032, 1835072, 2056832, 2097152],
...
		

Crossrefs

Programs

  • Maple
    gf:= proc(k) gf(k):= `if`(k=0, x, x*exp(gf(k-1))) end:
    A:= proc(n, k) A(n, k):= n!*coeff(series(gf(k), x, n+1), x, n) end:
    [seq([seq(A(n, d), d=0..n-1)], n=1..12)];
  • Mathematica
    gf[k_] := gf[k] = If[k == 0, x, x*E^gf[k-1]]; a[n_, k_] := n!*Coefficient[Series[gf[k], {x, 0, n+1}], x, n]; Table[Table[a[n, d], {d, 0, n-1}], {n, 1, 12}] // Flatten (* Jean-François Alcover, Mar 07 2014, after Maple *)

A291203 Number F(n,h,t) of forests of t labeled rooted trees with n vertices such that h is the maximum of 0 and the tree heights; triangle of triangles F(n,h,t), n>=0, h=0..n, t=0..n-h, read by layers, then by rows.

Original entry on oeis.org

1, 0, 1, 0, 0, 0, 1, 0, 2, 0, 0, 0, 0, 1, 0, 3, 6, 0, 6, 0, 0, 0, 0, 0, 1, 0, 4, 24, 12, 0, 36, 24, 0, 24, 0, 0, 0, 0, 0, 0, 1, 0, 5, 80, 90, 20, 0, 200, 300, 60, 0, 300, 120, 0, 120, 0, 0, 0, 0, 0, 0, 0, 1, 0, 6, 240, 540, 240, 30, 0, 1170, 3000, 1260, 120, 0, 3360, 2520, 360, 0, 2520, 720, 0, 720, 0
Offset: 0

Views

Author

Alois P. Heinz, Aug 20 2017

Keywords

Comments

Positive elements in column t=1 give A034855.
Elements in rows h=0 give A023531.
Elements in rows h=1 give A059297.
Positive row sums per layer give A235595.
Positive column sums per layer give A061356.

Examples

			n h\t: 0   1   2  3  4 5 : A235595 : A061356          : A000272
-----+-------------------+---------+------------------+--------
0 0  : 1                 :         :                  : 1
-----+-------------------+---------+------------------+--------
1 0  : 0   1             :      1  :   .              :
1 1  : 0                 :         :   1              : 1
-----+-------------------+---------+------------------+--------
2 0  : 0   0   1         :      1  :   .   .          :
2 1  : 0   2             :      2  :   .              :
2 2  : 0                 :         :   2   1          : 3
-----+-------------------+---------+------------------+--------
3 0  : 0   0   0  1      :      1  :   .   .   .      :
3 1  : 0   3   6         :      9  :   .   .          :
3 2  : 0   6             :      6  :   .              :
3 3  : 0                 :         :   9   6   1      : 16
-----+-------------------+---------+------------------+--------
4 0  : 0   0   0  0  1   :      1  :   .   .   .  .   :
4 1  : 0   4  24 12      :     40  :   .   .   .      :
4 2  : 0  36  24         :     60  :   .   .          :
4 3  : 0  24             :     24  :   .              :
4 4  : 0                 :         :  64  48  12  1   : 125
-----+-------------------+---------+------------------+--------
5 0  : 0   0   0  0  0 1 :      1  :   .   .   .  . . :
5 1  : 0   5  80 90 20   :    195  :   .   .   .  .   :
5 2  : 0 200 300 60      :    560  :   .   .   .      :
5 3  : 0 300 120         :    420  :   .   .          :
5 4  : 0 120             :    120  :   .              :
5 5  : 0                 :         : 625 500 150 20 1 : 1296
-----+-------------------+---------+------------------+--------
		

Crossrefs

Programs

  • Maple
    b:= proc(n, t, h) option remember; expand(`if`(n=0 or h=0, x^(t*n), add(
           binomial(n-1, j-1)*j*x^t*b(j-1, 0, h-1)*b(n-j, t, h), j=1..n)))
        end:
    g:= (n, h)-> b(n, 1, h)-`if`(h=0, 0, b(n, 1, h-1)):
    F:= (n, h, t)-> coeff(g(n, h), x, t):
    seq(seq(seq(F(n, h, t), t=0..n-h), h=0..n), n=0..8);
  • Mathematica
    b[n_, t_, h_] := b[n, t, h] = Expand[If[n == 0 || h == 0, x^(t*n), Sum[
         Binomial[n-1, j-1]*j*x^t*b[j-1, 0, h-1]*b[n-j, t, h], {j, 1, n}]]];
    g[n_, h_] := b[n, 1, h] - If[h == 0, 0, b[n, 1, h - 1]];
    F[n_, h_, t_] := Coefficient[g[n, h], x, t];
    Table[Table[Table[F[n, h, t], {t, 0, n - h}], {h, 0, n}], {n, 0, 8}] // Flatten (* Jean-François Alcover, Mar 17 2022, after Alois P. Heinz *)

Formula

Sum_{i=0..n} F(n,i,n-i) = A243014(n) = 1 + A038154(n).
Sum_{d=0..n} Sum_{i=0..d} F(n,i,d-i) = A000272(n+1).
Sum_{h=0..n} Sum_{t=0..n-h} t * F(n,h,t) = A089946(n-1) for n>0.
Sum_{h=0..n} Sum_{t=0..n-h} (h+1) * F(n,h,t) = A234953(n+1) for n>0.
Sum_{h=0..n} Sum_{t=0..n-h} (h+1)*(n+1) * F(n,h,t) = A001854(n+1) for n>0.
Sum_{t=0..n-1} F(n,1,t) = A235596(n+1).
F(2n,n,n) = A126804(n) for n>0.
F(n,0,n) = 1 = A000012(n).
F(n,1,1) = n = A001477(n) for n>1.
F(n,n-1,1) = n! = A000142(n) for n>0.
F(n,1,n-1) = A002378(n-1) for n>0.
F(n,2,1) = A000551(n).
F(n,3,1) = A000552(n).
F(n,4,1) = A000553(n).
F(n,1,2) = A001788(n-1) for n>2.
F(n,0,0) = A000007(n).
Showing 1-4 of 4 results.