A235810 Numbers n such that n^3 has one or more occurrences of exactly eight different digits.

289, 297, 302, 319, 467, 494, 515, 557, 562, 595, 621, 623, 676, 682, 709, 712, 721, 862, 887, 909, 939, 945, 949, 963, 984, 987, 1012, 1015, 1016, 1025, 1029, 1043, 1049, 1065, 1075, 1087, 1104, 1106, 1107, 1114, 1118, 1132, 1137, 1154, 1161, 1167, 1178

Offset: 1

Author

Colin Barker, Jan 19 2014

Keywords

• nonn
• base

Examples

			289 is in the sequence because 289^3 = 24137569, which contains exactly eight different digits.
		

Links

• Colin Barker, Table of n, a(n) for n = 1..1000

Crossrefs

Cf. A030292, A155146, A155147, A235807-A235809, A235811, A119735.

Programs

Magma

[n: n in [0..1200] | #Set(Intseq(n^3)) eq 8]; // Vincenzo Librandi, Nov 07 2014

PARI

s=[]; for(n=1, 1500, if(#vecsort(eval(Vec(Str(n^3))),,8)==8, s=concat(s, n))); s

Python

A235810_list, m = [], [6, -6, 1, 0]
for n in range(1,10**3+1):
    for i in range(3):
        m[i+1] += m[i]
    if len(set(str(m[-1]))) == 8:
        A235810_list.append(n) # Chai Wah Wu, Nov 05 2014