cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-4 of 4 results.

A241717 The number of P-positions in the game of Nim with up to 3 piles, allowing for piles of zero, such that the number of objects in the largest pile is n.

Original entry on oeis.org

1, 3, 3, 9, 3, 9, 15, 21, 3, 9, 15, 21, 27, 33, 39, 45, 3, 9, 15, 21, 27, 33, 39, 45, 51, 57, 63, 69, 75, 81, 87, 93, 3, 9, 15, 21, 27, 33, 39, 45, 51, 57, 63, 69, 75, 81, 87, 93, 99, 105, 111, 117, 123, 129, 135, 141, 147, 153, 159, 165, 171
Offset: 0

Views

Author

Tanya Khovanova and Joshua Xiong, Apr 27 2014

Keywords

Comments

This is the finite difference of A236305.
Starting from index 1 all elements are divisible by 3, and can be grouped into sets of size 2^k of an arithmetic progression 6n-3.
It appears that the sum of all terms of the first n rows of triangle gives A000302(n-1), see Example section. - Omar E. Pol, May 01 2015

Examples

			If the largest number is 1, then there should be exactly two piles of size 1 and one empty pile. There are 3 ways to permute this configuration, so a(1)=3.
From _Omar E. Pol_, Feb 26 2015: (Start)
Also written as an irregular triangle in which the row lengths are the terms of A011782, the sequence begins:
1;
3;
3, 9;
3, 9, 15, 21;
3, 9, 15, 21, 27, 33, 39, 45;
3, 9, 15, 21, 27, 33, 39, 45, 51, 57, 63, 69, 75, 81, 87, 93;
...
Observation: the first six terms of the right border coincide with the first six terms of A068156.
(End)
From _Omar E. Pol_, Apr 20 2015: (Start)
An illustration of initial terms in the fourth quadrant of the square grid:
---------------------------------------------------------------------------
n   a(n)             Compact diagram
---------------------------------------------------------------------------
.            _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _
0    1      |_| |_  |_ _ _  |_ _ _ _ _ _ _  |
1    3      |_ _| | |_ _  | |_ _ _ _ _ _  | |
2    3      | |_ _| |_  | | |_ _ _ _ _  | | |
3    9      |_ _ _ _| | | | |_ _ _ _  | | | |
4    3      | | | |_ _| | | |_ _ _  | | | | |
5    9      | | |_ _ _ _| | |_ _  | | | | | |
6   15      | |_ _ _ _ _ _| |_  | | | | | | |
7   21      |_ _ _ _ _ _ _ _| | | | | | | | |
8    3      | | | | | | | |_ _| | | | | | | |
9    9      | | | | | | |_ _ _ _| | | | | | |
10  15      | | | | | |_ _ _ _ _ _| | | | | |
11  21      | | | | |_ _ _ _ _ _ _ _| | | | |
12  27      | | | |_ _ _ _ _ _ _ _ _ _| | | |
13  33      | | |_ _ _ _ _ _ _ _ _ _ _ _| | |
14  39      | |_ _ _ _ _ _ _ _ _ _ _ _ _ _| |
15  45      |_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _|
.
It appears that a(n) is also the number of cells in the n-th region of the diagram, and A236305(n) is also the total number of cells after n-th stage.
(End)
		

Crossrefs

Cf. A011782, A068156, A236305 (partial sums), A241718 (4 piles), A241731 (5 piles).

Programs

  • Mathematica
    Table[Length[Select[Flatten[Table[{n, k, BitXor[n, k]}, {n, 0, a}, {k, 0, a}], 1], Max[#] == a &]], {a, 0, 100}]

Formula

If b = floor(log_2(n)) is the number of digits in the binary representation of n and c = n + 1 - 2^b, then a(n) = 6*c-3.

A256534 Number of ON cells at n-th stage in simple 2-dimensional cellular automaton (see Comments lines for definition).

Original entry on oeis.org

0, 4, 16, 28, 64, 76, 112, 172, 256, 268, 304, 364, 448, 556, 688, 844, 1024, 1036, 1072, 1132, 1216, 1324, 1456, 1612, 1792, 1996, 2224, 2476, 2752, 3052, 3376, 3724, 4096, 4108, 4144, 4204, 4288, 4396, 4528, 4684, 4864, 5068, 5296, 5548, 5824, 6124, 6448, 6796, 7168, 7564, 7984, 8428, 8896, 9388, 9904, 10444, 11008
Offset: 0

Views

Author

Omar E. Pol, Apr 22 2015

Keywords

Comments

On the infinite square grid at stage 0 there are no ON cells, so a(0) = 0.
At stage 1, four cells are turned ON forming a square, so a(1) = 4.
If n is a power of 2 so the structure is a square of side length 2n that contains (2n)^2 ON cells.
The structure grows by the four corners as square waves forming layers of ON cells up the next square structure, and so on (see example).
Has the same rules as A256530 but here a(1) = 4 not 1.
Has a smoother behavior than A160410 with which shares infinitely many terms (see example).
A261695, the first differences, gives the number of cells turned ON at n-th stage.

Examples

			With the positive terms written as an irregular triangle in which the row lengths are the terms of A011782 the sequence begins:
4;
16;
28,     64;
76,    112,  172,  256;
268,   304,  364,  448,  556,  688,  844, 1024;
...
Right border gives the elements of A000302 greater than 1.
This triangle T(n,k) shares with the triangle A160410 the terms of the column k, if k is a power of 2, for example, both triangles share the following terms: 4, 16, 28, 64, 76, 112, 256, 268, 304, 448, 1024, etc.
.
Illustration of initial terms, for n = 1..10:
.       _ _ _ _                         _ _ _ _
.      |  _ _  |                       |  _ _  |
.      | |  _|_|_ _ _ _ _ _ _ _ _ _ _ _|_|_  | |
.      | |_|  _ _ _ _ _ _     _ _ _ _ _ _  |_| |
.      |_ _| |  _ _ _ _  |   |  _ _ _ _  | |_ _|
.          | | |  _ _  | |   | |  _ _  | | |
.          | | | |  _|_|_|_ _|_|_|_  | | | |
.          | | | |_|  _ _     _ _  |_| | | |
.          | | |_ _| |  _|_ _|_  | |_ _| | |
.          | |_ _ _| |_|  _ _  |_| |_ _ _| |
.          |       |   | |   | |   |       |
.          |  _ _ _|  _| |_ _| |_  |_ _ _  |
.          | |  _ _| | |_ _ _ _| | |_ _  | |
.          | | |  _| |_ _|   |_ _| |_  | | |
.          | | | | |_ _ _ _ _ _ _ _| | | | |
.          | | | |_ _| | |   | | |_ _| | | |
.       _ _| | |_ _ _ _| |   | |_ _ _ _| | |_ _
.      |  _| |_ _ _ _ _ _|   |_ _ _ _ _ _| |_  |
.      | | |_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _| | |
.      | |_ _| |                       | |_ _| |
.      |_ _ _ _|                       |_ _ _ _|
.
After 10 generations there are 304 ON cells, so a(10) = 304.
		

Crossrefs

Programs

  • Mathematica
    {0}~Join~Flatten@ Table[4^i + 3 (2 j)^2, {i, 6}, {j, 0, 2^(i - 1) - 1}] (* Michael De Vlieger, Nov 03 2022 *)

Formula

For i = 1 to z: for j = 0 to 2^(i-1)-1: n = n+1: a(n) = 4^i + 3*(2*j)^2: next j: next i
It appears that a(n) = 4 * A236305(n-1), n >= 1.

A241522 The number of P-positions in the game of Nim with up to 4 piles, allowing for piles of zero, such that the number of objects in each pile does not exceed n.

Original entry on oeis.org

1, 8, 21, 64, 89, 168, 301, 512, 561, 712, 965, 1344, 1801, 2408, 3165, 4096, 4193, 4488, 4981, 5696, 6585, 7720, 9101, 10752, 12433, 14408, 16677, 19264, 22121, 25320, 28861, 32768, 32961, 33544, 34517, 35904, 37657, 39848, 42477, 45568, 48881, 52680, 56965, 61760, 67017
Offset: 0

Views

Author

Tanya Khovanova and Joshua Xiong, Apr 24 2014

Keywords

Comments

P-positions in the game of Nim are tuples of numbers with a Nim-Sum equal to zero. (0,1,1,0) is considered different from (1,0,1,0).
Partial sums of A241718.

Examples

			If the largest number is 1, then there should be an even number of piles of size 1. Thus, a(1)=8.
		

Crossrefs

Cf. A236305 (3 piles), A241523 (5 piles).
Cf. A241718 (first differences).

Programs

  • Mathematica
    Table[Length[Select[Flatten[Table[{n, k, j, BitXor[n, k, j]}, {n, 0, a}, {k, 0, a}, {j, 0, a}], 2], #[[4]] <= a &]], {a, 0, 50}]

Formula

If b = floor(log_2(n)) is the number of digits in the binary representation of n and c = n + 1 - 2^b, then a(n) = 2^(3*b) + 6*c^2*2^b + a(c-1).
a(2^n-1) = 2^(3*n).

A241523 The number of P-positions in the game of Nim with up to 5 piles, allowing for piles of zero, such that the number of objects in each pile does not exceed n.

Original entry on oeis.org

1, 16, 61, 256, 421, 976, 2101, 4096, 4741, 6736, 10261, 15616, 23221, 33616, 47461, 65536, 68101, 75856, 88981, 107776, 132661, 164176, 202981, 249856, 305701, 371536, 448501, 537856, 640981, 759376, 894661, 1048576, 1058821, 1089616
Offset: 0

Views

Author

Tanya Khovanova and Joshua Xiong, Apr 24 2014

Keywords

Comments

P-positions in the game of Nim are tuples of numbers with a Nim-Sum equal to zero. (0,1,1,0,0) is considered different from (1,0,1,0,0).
a(2^n-1) = 2^(4n).

Examples

			If the largest number is not more than 1, then there should be an even number of piles of size 1. We can choose the first four piles to be either 0 or 1, then the last pile is uniquely defined. Thus, a(1)=16.
		

Crossrefs

Cf. A236305 (3 piles), A241522 (4 piles).
Cf. A241731 (first differences).

Programs

  • Mathematica
    Table[Length[Select[Flatten[Table[{n, k, j, i, BitXor[n, k, j, i]}, {n, 0, a}, {k, 0, a}, {j, 0, a}, {i, 0, a}], 3], #[[5]] <= a &]], {a, 0, 35}]

Formula

If b = floor(log_2(n)) is the number of digits in the binary representation of n and c = n + 1 - 2^b, then a(n) = 2^(4*b) + 10*2^(2*b)*c^2 + 5*c^4.
Showing 1-4 of 4 results.