cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-5 of 5 results.

A236850 After 0 and 1, numbers n whose binary representation encodes such a polynomial over GF(2) that all its irreducible factors (their binary codes) are primes in N (terms of A091206).

Original entry on oeis.org

0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 44, 45, 46, 47, 48, 49, 51, 52, 53, 54, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71
Offset: 1

Views

Author

Antti Karttunen, Feb 02 2014

Keywords

Comments

To determine whether n belongs to this sequence: first find a unique multiset of terms i, j, ..., k (terms not necessarily distinct) from A014580 for which i x j x ... x k = n, where x stands for the carryless multiplication (A048720). If and only if NONE of those i, j, ..., k is a composite (in other words, if all are primes in N, i.e. terms of A091206), then n is a member.
Equally, numbers which can be constructed as p x q x ... x r, where p, q, ..., r are terms of A091206. (Compare to the definition of A236860.)
Also fixed points of A236851(n). Proof: if k is a term of this sequence, the operation described in A236851 reduces to an identity operation. On the other hand, if k is not a term of this sequence, then it contains at least one irreducible GF(2)[X]-factor which is a composite in N, which is thus "broken" by A236851 to two or more separate GF(2)[X]-factors (either irreducible or not), and because the original factor was irreducible, and GF(2)[X] is a unique factorization domain, the new product computed over the new set of factors (with one or more "broken" pieces) cannot be equal to the original k. (Compare this to how primes are "broken" in a similar way in A235027, also A235145.)
Also by similar to above reasoning, positions where A234742(n) = A236837(n).
This is a subsequence of A236841, from which this differs for the first time at n=43, where A236841(43)=43, while from here 43 is missing, and a(43)=44.

Examples

			25 is the first term not included, as although it encodes an irreducible polynomial in GF(2)[X]: X^4 + X^3 + 1 (binary code 11001), it is composite in Z, thus not in A091206, but in A091214.
27 is included, as it factors as 5 x 7, and both factors are present in A091206.
37 is included, as it is a member of A091206 (irreducible in both Z and GF(2)[X]).
43 is NOT included because, even although it is a prime in Z, it factors as 3 x 25 in GF(2)[X]. Of these, only 3 is a term of A091206, while 25 belongs to A091214, as it further divides to 5*5.
		

Crossrefs

Subsequence of A236841.
Subsequence: A235032.

A236842 Numbers that occur as results of remultiplication (GF(2)[X] -> N) of some number; A234742 sorted and duplicates removed.

Original entry on oeis.org

0, 1, 2, 3, 4, 6, 7, 8, 9, 11, 12, 13, 14, 16, 18, 19, 21, 22, 24, 25, 26, 27, 28, 31, 32, 33, 36, 37, 38, 39, 41, 42, 44, 47, 48, 49, 50, 52, 54, 55, 56, 57, 59, 61, 62, 63, 64, 66, 67, 72, 73, 74, 75, 76, 77, 78, 81, 82, 84, 87, 88, 91, 93, 94, 96, 97, 98, 99, 100, 103
Offset: 1

Views

Author

Antti Karttunen, Jan 31 2014

Keywords

Comments

This sequence gives the range of A234742.
After 0 and 1 these are numbers n that have such a multiset of prime divisors p, q, ..., w (p * q * ... * w = n, with p, q, ..., w not necessarily distinct) that it can be arranged so that in at least one subset of divisors of n: (p, q, w), (pq, w), (pw, q), (p, qw), (pqw), ..., all divisors (for example, in the second case: pq and w) encode by their binary representations irreducible factors of polynomial ring over GF(2) (i.e., all occur in A014580) and their (ordinary) product is n.
Above condition implies that none of the terms of A091209 occur here.

Crossrefs

Complement: A236844. A236860 is a subsequence.
Positions of nonzero terms in A236853.

Formula

Use the characteristic function A236862(n) to determine whether n is a term of this sequence or not.
Specifically:
All numbers encoding an irreducible polynomial in GF(2)[X] (A014580) occur in this sequence. This means that a prime is in this sequence if and only if it is in A091206.
On the other hand, a composite integer n is in this sequence if and only if it is either in A014580 or it has such a proper factor k (1

A236848 Numbers that have at least one prime divisor encoding a reducible polynomial in ring GF(2)[X]; multiples of terms of A091209.

Original entry on oeis.org

5, 10, 15, 17, 20, 23, 25, 29, 30, 34, 35, 40, 43, 45, 46, 50, 51, 53, 55, 58, 60, 65, 68, 69, 70, 71, 75, 79, 80, 83, 85, 86, 87, 89, 90, 92, 95, 100, 101, 102, 105, 106, 107, 110, 113, 115, 116, 119, 120, 125, 127, 129, 130, 135, 136, 138, 139, 140, 142, 145, 149, 150
Offset: 1

Author

Antti Karttunen, Jan 31 2014

Keywords

Comments

Numbers that are divisible by at least one prime whose binary representation encodes a polynomial which is reducible in polynomial ring GF(2)[X].

Crossrefs

Disjoint union of A236844 and A236849.
Complement: A236860.

A236849 Numbers that occur as results of remultiplication (GF(2)[X] -> N) of some number and have at least one prime divisor encoding a reducible polynomial in ring GF(2)[X].

Original entry on oeis.org

25, 50, 55, 75, 87, 100, 110, 115, 145, 150, 165, 174, 175, 185, 200, 203, 213, 220, 225, 230, 253, 261, 275, 285, 290, 299, 300, 301, 319, 325, 330, 345, 348, 350, 355, 357, 370, 375, 385, 391, 395, 400, 406, 415, 425, 426, 435, 440, 445, 450, 460, 475, 477, 495, 505, 506, 515, 522, 525, 529, 535, 545, 550, 555
Offset: 1

Author

Antti Karttunen, Jan 31 2014

Keywords

Comments

Terms of A236842 (A234742) that are divisible by at least one of the primes in A091209.
a(4)=75, is the first term here which does not occur in A236834. On the other hand, A236834(5)=91 is the first of its terms that does not occur here.

Crossrefs

Setwise difference A236848 \ A236844, and also A236842 \ A236860.

A236852 Remultiply n first "downward", from N to GF(2)[X], and then remultiply that result back "upward", from GF(2)[X] to N: a(n) = A234742(A234741(n)).

Original entry on oeis.org

0, 1, 2, 3, 4, 9, 6, 7, 8, 9, 18, 11, 12, 13, 14, 27, 16, 81, 18, 19, 36, 21, 22, 39, 24, 81, 26, 27, 28, 33, 54, 31, 32, 33, 162, 63, 36, 37, 38, 39, 72, 41, 42, 75, 44, 81, 78, 47, 48, 49, 162, 243, 52, 57, 54, 99, 56, 57, 66, 59, 108, 61, 62, 63, 64, 117, 66, 67, 324
Offset: 0

Author

Antti Karttunen, Feb 02 2014

Keywords

Comments

This sequence appears to be completely multiplicative with a(p) = A234742(p) although neither A234741 or A234742 are even multiplicative. Terms tested up to n = 10^7. - Andrew Howroyd, Aug 01 2018
Yes, this is true. Consider for example n = p*q*r*r, where p, q, r are primes in N. Then A234741(n) = p1 x q1 x q2 x q3 x r1 x r2 x r1 x r2, where p1, q1, r1, ..., are the irreducible factors of p, q, r when factored over GF(2), and x stands for multiplication in ring GF(2)[X] (A048720). [Note that these irreducible factors are not necessarily primes in N, except p1 (= p), which must be a term of A091206. Also, A234741(p) = p for any prime p.] Next, a(n) = A234742(p1 x q1 x q2 x q3 x r1 x r2 x r1 x r2) = p1 * q1 * q2 * q3 * r1 * r2 * r1 * r2, which can be obtained also as a(p)*a(q)*a(r)*a(r), thus proving the multiplicativity. - Antti Karttunen, Aug 02 2018

Examples

			From _Antti Karttunen_, Aug 02 2018: (Start)
For n = 3, we have A234741(3) = 3 = 11 in binary, which encodes a (0,1)-polynomial x+1, which is irreducible over GF(2) thus A234742(3) = 3 and  a(3) = 3.
For n = 5, we have A234741(5) = 5 = 101 in binary, which encodes a (0,1)-polynomial x^2 + 1, which factorizes as (x+1)(x+1) when factored over GF(2), that is 5 = A048720(3,3), thus it follows that A234742(5) = 3*3 = 9, and a(5) = 9.
For n = 9 = 3*3, we have A234741(9) = A048720(3,3) = 5, and A234742(5) = 9 as shown above. Also by multiplicativity, we have a(3*3) = a(3)*a(3) = 3*3 = 9.
(End)
		

Crossrefs

Programs

Formula

a(n) = A234742(A234741(n)).

Extensions

Keyword mult added after Andrew Howroyd's observation. - Antti Karttunen, Aug 02 2018
Showing 1-5 of 5 results.