A243055 Difference between the indices of the smallest and the largest prime dividing n: If n = p_i * ... * p_k, where p_i <= ... <= p_k, where p_h = A000040(h), then a(n) = (k-i), a(1) = 0 by convention.

0, 0, 0, 0, 0, 1, 0, 0, 0, 2, 0, 1, 0, 3, 1, 0, 0, 1, 0, 2, 2, 4, 0, 1, 0, 5, 0, 3, 0, 2, 0, 0, 3, 6, 1, 1, 0, 7, 4, 2, 0, 3, 0, 4, 1, 8, 0, 1, 0, 2, 5, 5, 0, 1, 2, 3, 6, 9, 0, 2, 0, 10, 2, 0, 3, 4, 0, 6, 7, 3, 0, 1, 0, 11, 1, 7, 1, 5, 0, 2, 0, 12, 0, 3, 4, 13, 8, 4, 0, 2

Offset: 1

Author

Antti Karttunen, May 31 2014

Keywords

• nonn

Comments

For n>=1, A100484(n+1) gives the position where n occurs for the first time (setting also the records for the sequence).

a(n) = the difference between the largest and the smallest parts of the partition having Heinz number n. We define the Heinz number of a partition p = [p_1, p_2, ..., p_r] as Product(p_j-th prime, j=1...r) (concept used by Alois P. Heinz in A215366 as an "encoding" of a partition). For example, for the partition [1, 1, 2, 4, 10] we get 2*2*3*7*29 = 2436. Example: a(57) = 6; indeed, the partition having Heinz number 57 = 3*19 is [2, 8]. - Emeric Deutsch, Jun 04 2015

Links

• Antti Karttunen, Table of n, a(n) for n = 1..10000
• Index entries for sequences computed from indices in prime factorization

Crossrefs

Differs from A242411 for the first time at n=30.

A000961 gives the positions of zeros.

Cf. A243056, A241917, A241919, A049084, A027748, A055396, A061395, A100484, A215366.

Programs

Maple

with(numtheory):
a:= n-> `if`(n=1, 0, (f-> pi(max(f[]))-pi(min(f[])))(factorset(n))):
seq(a(n), n=1..100);  # Alois P. Heinz, Jun 04 2015

Mathematica

a[1]=0; a[n_] := Function[{f}, PrimePi[Max[f]] - PrimePi[Min[f]]][FactorInteger[n][[All, 1]]]; Table[a[n], {n, 1, 100}] (* Jean-François Alcover, Jul 29 2015, after Alois P. Heinz *)

Python

from sympy import primepi, primefactors
def A243055(n): return primepi(max(p:=primefactors(n),default=0))-primepi(min(p,default=0)) # Chai Wah Wu, Oct 10 2023

Scheme

(define (A243055 n) (- (A061395 n) (A055396 n)))

Formula

If n = p_i * ... * p_k, where p_i <= ... <= p_k are not necessarily distinct primes (sorted into nondescending order) in the prime factorization of n, where p_i = A000040(i), then a(n) = (k-i).

a(n) = A061395(n) - A055396(n).