A243224 Number of odd divisors d of n such that d > 1 and d(1+d/3)/2 <= n <= 3d(d-1)/2.
0, 0, 1, 0, 0, 1, 0, 0, 1, 1, 0, 0, 0, 1, 1, 0, 0, 1, 0, 1, 1, 0, 0, 0, 1, 0, 1, 1, 0, 1, 0, 0, 1, 0, 1, 1, 0, 0, 1, 0, 0, 1, 0, 1, 2, 0, 0, 0, 1, 0, 0, 1, 0, 1, 1, 1, 0, 0, 0, 1, 0, 0, 2, 0, 1, 1, 0, 1, 0, 0, 0, 1, 0, 0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 1, 1, 0, 0
Offset: 1
Keywords
Examples
a(6) = 1 because 3, the unique odd divisor > 1 of 6 satisfies 3(1+3/3)/2 <= 6 <= 3.3(3-1)/2.
Links
- Jean-Christophe Hervé, Table of n, a(n) for n = 1..10000
- M. A. Nyblom and C. Evans, On the enumeration of partitions with summands in arithmetic progression, Australasian Journal of Combinatorics, Vol. 28 (2003), pp. 149-159.
Crossrefs
Cf. A243223.
Programs
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PARI
a(n) = sumdiv(n, d, (d > 1) && (d % 2) && (d*(1+d/3)/2 <= n) && (n <= 3*d*(d-1)/2)); \\ Michel Marcus, Jun 02 2014
Comments