cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A244445 a(n) = ceiling(A002386(n+1)/A002386(n)).

Original entry on oeis.org

2, 3, 4, 4, 2, 5, 2, 2, 2, 8, 2, 2, 2, 5, 3, 2, 2, 3, 2, 2, 3, 4, 2, 3, 3, 2, 2, 3, 2, 3, 2, 2, 2, 2, 3, 2, 2, 2, 2, 4, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 3, 2, 2, 3, 3, 2, 2, 6, 2, 2, 26, 2, 2, 3, 2, 2, 2, 2, 2, 2, 2, 5, 2, 3, 2, 2
Offset: 1

Views

Author

Farideh Firoozbakht, Oct 08 2014

Keywords

Comments

Obviously, for all n, a(n) is greater than one. According to the definition of a(n) for all n, A002386(n+1) < a(n)*A002386(n). So if n is less than 79 and not equal to 64, then A002386(n+1) < 8*A002386(n). [Updated John W. Nicholson, Nov 28 2019]
Also for all n < 79, A002386(n+1) < 26*A002386(n). [Updated John W. Nicholson, Nov 28 2019]
The strictly increasing terms of the sequence: 2, 3, 4, 5, 8, 26, ?, ... .
Record values are {2, 3, 4, 5, 8, 26} = {a(1), a(2), a(3), a(6), a(10), a(64)}.
A very difficult question: "What is the next term of the above sequence?" namely "What is the next term of the sequence which is greater than a(64) = 26 ?". I don't think that in this century anyone can find the answer.

Examples

			a(10) = ceiling(A002386(11)/A002386(10)) = ceiling(9551/1327) = 8.
		

Crossrefs

Formula

a(n) = ceiling(A002386(n+1)/A002386(n)) = floor(A002386(n+1)/A002386(n))+1.