cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-6 of 6 results.

A245709 Fixed points of A245705 and A245706.

Original entry on oeis.org

1, 2, 3, 4, 5, 6, 8, 10, 12, 16, 20, 24, 32, 40, 43, 48, 53, 64, 80, 86, 96, 106, 128, 160, 172, 192, 212, 249, 256, 320, 344, 384, 417, 424, 498, 512, 640, 688, 768, 834, 848, 996, 1024, 1280, 1321, 1376, 1536, 1668, 1696, 1992, 2048, 2560, 2642, 2752, 3072, 3336, 3392, 3984, 4096, 5120, 5284, 5504, 5545, 6144, 6672, 6784, 6827, 7081, 7968, 8192
Offset: 1

Views

Author

Antti Karttunen, Jul 30 2014

Keywords

Comments

The odd terms less than 2^25 are: 1, 3, 5, 43, 53, 249, 417, 1321, 5545, 6827, 7081, 8535, 1485465, 1876261, 3298409, 13937375.
Contains also all such numbers k that A245608(k) = A245708(k), because that condition implies that A245607(A245708(k)) = k = A245707(A245608(k)). Conjecture: contains no numbers outside of that set, that is, for all n, A245608(a(n)) = A245708(a(n)).

Crossrefs

A000079 is a subsequence.

Programs

A245712 Permutation of natural numbers, odd bisection of A245706 incremented by one and halved: a(n) = (1+A245706((2*n)-1)) / 2.

Original entry on oeis.org

1, 2, 3, 6, 4, 14, 5, 38, 10, 8, 26, 330, 18, 46, 283, 42, 11, 34, 7, 50, 70, 22, 17, 326, 37, 58, 27, 32, 53, 9590, 554, 4438, 278, 174, 9, 16, 15, 142, 25, 226, 146, 658, 105, 310, 1190, 806, 1770, 524, 51, 5258, 66, 5302, 35, 518, 17739, 1054, 19030, 542, 5550, 8054, 35498, 4434, 29, 810, 1106, 72, 75, 28, 63, 166, 83, 150, 44
Offset: 1

Views

Author

Antti Karttunen, Jul 30 2014

Keywords

Crossrefs

Inverse: A245711.

Programs

Formula

a(n) = (1+A245706((2*n)-1)) / 2.

A245606 Permutation of natural numbers: a(1) = 1, a(2n) = 1 + A003961(a(n)), a(2n+1) = A003961(1+a(n)). [Where A003961(n) shifts the prime factorization of n one step left].

Original entry on oeis.org

1, 2, 3, 4, 5, 6, 9, 10, 7, 8, 15, 16, 11, 26, 21, 22, 13, 12, 27, 28, 25, 36, 81, 82, 19, 14, 45, 52, 125, 56, 39, 40, 29, 18, 33, 46, 17, 126, 99, 100, 31, 50, 51, 226, 41, 626, 129, 130, 89, 24, 63, 34, 35, 176, 87, 154, 59, 344, 825, 298, 115, 86, 189, 190, 43, 32, 105, 76, 23, 66, 57, 88, 53, 20
Offset: 1

Views

Author

Antti Karttunen, Jul 29 2014

Keywords

Comments

The even bisection halved gives A245608. The odd bisection incremented by one and halved gives A245708.

Crossrefs

Programs

Formula

a(1) = 1, a(2n) = A243501(a(n)), a(2n+1) = A003961(1+a(n)).
As a composition of related permutations:
a(n) = A064216(A245608(n)).

A245608 Permutation of natural numbers, the even bisection of A245606 halved: a(n) = A245606(2*n)/2.

Original entry on oeis.org

1, 2, 3, 5, 4, 8, 13, 11, 6, 14, 18, 41, 7, 26, 28, 20, 9, 23, 63, 50, 25, 113, 313, 65, 12, 17, 88, 77, 172, 149, 43, 95, 16, 38, 33, 44, 10, 413, 163, 221, 19, 74, 48, 191, 22, 476, 118, 179, 49, 68, 138, 29, 39, 527, 78, 215, 31, 635, 1593, 227, 102, 71, 688, 242, 24, 122, 193, 104, 15, 98, 58, 176, 30, 32, 123
Offset: 1

Views

Author

Antti Karttunen, Jul 29 2014

Keywords

Crossrefs

Programs

Formula

a(n) = A245606(2*n)/2.
As a composition of related permutations:
a(n) = A048673(A245606(n)).
a(n) = A245708(A245706(n)).
Other identities:
For all n >= 0, a(2^n) = A245708(2^n). Moreover, A245709 gives all such k that a(k) = A245708(k).

A245705 Permutation of natural numbers: a(n) = A245607(A245708(n)).

Original entry on oeis.org

1, 2, 3, 4, 5, 6, 9, 8, 13, 10, 7, 12, 37, 18, 19, 16, 69, 26, 17, 20, 33, 14, 277, 24, 213, 74, 11, 36, 73, 38, 71, 32, 45, 138, 25, 52, 1109, 34, 457, 40, 173, 66, 43, 28, 549, 554, 3351, 48, 77, 426, 21, 148, 53, 22, 135, 72, 125, 146, 651, 76, 273, 142, 55, 64
Offset: 1

Views

Author

Antti Karttunen, Jul 30 2014

Keywords

Comments

The even bisection halved gives the sequence back. The odd bisection incremented by one and halved gives A245711.

Crossrefs

Inverse: A245706.
Fixed points: A245709.

Programs

Formula

a(n) = A245607(A245708(n)).

A245707 Permutation of natural numbers, the odd bisection of A245605 incremented by one and halved: a(n) = (1+A245605((2*n)-1))/2.

Original entry on oeis.org

1, 2, 3, 5, 4, 7, 9, 6, 19, 13, 8, 35, 11, 10, 17, 21, 18, 27, 139, 16, 23, 33, 14, 555, 51, 22, 37, 75, 36, 29, 105, 26, 67, 147, 278, 71, 165, 38, 53, 587, 12, 107, 83, 28, 25, 2219, 72, 43, 73, 20, 87, 41, 34, 291, 277, 210, 163, 31, 66, 149, 131, 330, 15, 229, 24, 39, 2347, 70, 49, 101
Offset: 1

Views

Author

Antti Karttunen, Jul 30 2014

Keywords

Crossrefs

Programs

Formula

a(n) = (1+A245605((2*n)-1))/2.
As a composition of related permutations:
a(1) = 1, and for n > 1, a(n) = 1+A245605(A064216(n)-1).
a(n) = A245706(A245607(n)).
Showing 1-6 of 6 results.