A270951 Numbers k such that k | A000129(k-1).
1, 7, 17, 23, 31, 41, 47, 71, 73, 79, 89, 97, 103, 113, 127, 137, 151, 167, 169, 191, 193, 199, 223, 233, 239, 241, 257, 263, 271, 281, 311, 313, 337, 353, 359, 367, 383, 385, 401, 409, 431, 433, 439, 449, 457, 463, 479, 487, 503, 521, 569, 577, 593, 599, 601, 607, 617, 631, 641, 647, 673, 719, 727, 743
Offset: 1
Examples
7 is a term because A000129(6) = 70 is divisible by 7.
Links
- Amiram Eldar, Table of n, a(n) for n = 1..10000
Programs
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Mathematica
Select[Range[1000], Divisible[Fibonacci[#-1, 2], #]&] (* Jean-François Alcover, Jun 06 2017 *)
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PARI
a000129(n) = ([2, 1; 1, 0]^n)[2, 1]; for(n=1, 1e3, if(Mod(a000129(n-1), n) == 0, print1(n, ", ")));
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PARI
is(n)=(Mod([2,1;1,0],n)^(n-1))[2,1]==0 \\ Charles R Greathouse IV, Sep 11 2022
Comments