cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A327171 a(n) = phi(n) * core(n), where phi is Euler totient function, and core gives the squarefree part of n.

Original entry on oeis.org

1, 2, 6, 2, 20, 12, 42, 8, 6, 40, 110, 12, 156, 84, 120, 8, 272, 12, 342, 40, 252, 220, 506, 48, 20, 312, 54, 84, 812, 240, 930, 32, 660, 544, 840, 12, 1332, 684, 936, 160, 1640, 504, 1806, 220, 120, 1012, 2162, 48, 42, 40, 1632, 312, 2756, 108, 2200, 336, 2052, 1624, 3422, 240, 3660, 1860, 252, 32, 3120, 1320
Offset: 1

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Author

Antti Karttunen, Sep 28 2019

Keywords

References

  • Steven R. Finch, Mathematical Constants II, Encyclopedia of Mathematics and Its Applications, Cambridge University Press, Cambridge, 2018, p. 161.

Crossrefs

Cf. A082473 (gives the terms in ascending order, with duplicates removed).
Cf. also A002618, A062355.

Programs

  • Magma
    [EulerPhi(n)*Squarefree(n): n in [1..100]]; // G. C. Greubel, Jul 13 2024
    
  • Mathematica
    Array[EulerPhi[#] (Sqrt@ # /. (c_: 1) a_^(b_: 0) :> (c a^b)^2) &, 66] (* Michael De Vlieger, Sep 29 2019, after Bill Gosper at A007913 *)
  • PARI
    A327171(n) = eulerphi(n)*core(n);
    
  • PARI
    A327171(n) = { my(f=factor(n)); prod (i=1, #f~, (f[i, 1]-1)*(f[i, 1]^(-1 + f[i, 2] + (f[i, 2]%2)))); };
    
  • Python
    from sympy.ntheory.factor_ import totient, core
    def A327171(n):
        return totient(n)*core(n) # Chai Wah Wu, Sep 29 2019
    
  • SageMath
    [euler_phi(n)*squarefree_part(n) for n in range(1,101)] # G. C. Greubel, Jul 13 2024

Formula

a(n) = A000010(n) * A007913(n).
Multiplicative with a(p^k) = (p-1) * p^((k-1)+(k mod 2)).
Sum_{n>=1} 1/a(n) = (Pi^2/6) * Product_{p prime} (1 + (p+1)/(p^2*(p-1))) = 3.96555686901754604330... - Amiram Eldar, Oct 16 2020
Sum_{k=1..n} a(k) ~ c * n^3, where c = (Pi^2/45) * Product_{p prime} (1 - 1/p^2 + 1/p^3 - 1/p^4) = 0.1500809164... . - Amiram Eldar, Dec 05 2022
a(n) = A000010(A053143(n)). - Amiram Eldar, Sep 15 2023
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