A249224 Lpf (n(n+11)/2): least prime dividing n(n+11)/2.
2, 13, 3, 2, 2, 3, 3, 2, 2, 3, 11, 2, 2, 5, 3, 2, 2, 3, 3, 2, 2, 3, 17, 2, 2, 13, 3, 2, 2, 3, 3, 2, 2, 3, 5, 2, 2, 7, 3, 2, 2, 3, 3, 2, 2, 3, 29, 2, 2, 5, 3, 2, 2, 3, 3, 2, 2, 3, 5, 2, 2, 31, 3, 2, 2, 3, 3, 2, 2, 3, 41, 2, 2, 5, 3, 2, 2, 3, 3, 2, 2, 3, 47, 2, 2, 43, 3, 2, 2, 3, 3, 2, 2, 3, 5, 2, 2, 7, 3, 2
Offset: 1
Links
- Zak Seidov, Table of n, a(n) for n = 1..10000
Programs
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Mathematica
FactorInteger[#(11+#)/2][[1,1]]& /@ Range[100]
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PARI
a(n) = my(f=factor(n*(n+11)/2)); f[1,1]; \\ Michel Marcus, Oct 23 2014
Formula
a(n) = A020639(n(n+11)/2).
Comments