A254472 Sixth partial sums of sixth powers (A001014).
1, 70, 1134, 9870, 59220, 275562, 1063530, 3552978, 10577385, 28652260, 71725108, 167911380, 371057232, 779831820, 1568210220, 3032733564, 5663906745, 10251608346, 18037546450, 30931714450, 51814612980, 84952851750, 136562787270, 215565263550, 334584493425
Offset: 1
Examples
First differences: 1, 63, 665, 3367, 11529, ... (A022522) -------------------------------------------------------------------------- The sixth powers: 1, 64, 729, 4096, 15625, ... (A001014) -------------------------------------------------------------------------- First partial sums: 1, 65, 794, 4890, 20515, ... (A000540) Second partial sums: 1, 66, 860, 5750, 26265, ... (A101093) Third partial sums: 1, 67, 927, 6677, 32942, ... (A254640) Fourth partial sums: 1, 68, 995, 7672, 40614, ... (A254645) Fifth partial sums: 1, 69, 1064, 8736, 49350, ... (A254683) Sixth partial sums: 1, 70, 1134, 9870, 59220, ... (this sequence)
Links
- Luciano Ancora, Table of n, a(n) for n = 1..1000
- Luciano Ancora, Partial sums of m-th powers with Faulhaber polynomials.
- Luciano Ancora, Pascal’s triangle and recurrence relations for partial sums of m-th powers.
- Index entries for linear recurrences with constant coefficients, signature (13,-78,286,-715,1287,-1716,1716,-1287,715,-286,78,-13,1).
Crossrefs
Programs
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Magma
[n*(1+n)*(2+n)*(3+n)^2*(4+n)*(5+n)*(6+n)*(-3+5*n+n^2)* (3+7*n+n^2)/665280: n in [1..30]]; // Vincenzo Librandi, Feb 15 2015
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Mathematica
Table[n (1 + n) (2 + n) (3 + n)^2 (4 + n) (5 + n) (6 + n) (- 3 + 5 n + n^2) (3 + 7 n + n^2)/665280, {n, 22}] (* or *) CoefficientList[Series[(- 1 - 57 x - 302 x^2 - 302 x^3 - 57 x^4 - x^5)/(- 1 + x)^13, {x, 0, 28}], x] Nest[Accumulate,Range[30]^6,6] (* Harvey P. Dale, Oct 02 2015 *)
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PARI
vector(50,n,n*(1 + n)*(2 + n)*(3 + n)^2*(4 + n)*(5 + n)*(6 + n)*(-3 + 5*n + n^2)*(3 + 7*n + n^2)/665280) \\ Derek Orr, Feb 19 2015
Formula
G.f.: (-x - 57*x^2 - 302*x^3 - 302*x^4 - 57*x^5 - x^6)/(- 1 + x)^13.
a(n) = n*(1 + n)*(2 + n)*(3 + n)^2*(4 + n)*(5 + n)*(6 + n)*(-3 + 5*n + n^2)*(3 + 7*n + n^2)/665280.
a(n) = 6*a(n-1) - 15*a(n-2) + 20*a(n-3) - 15*a(n-4) + 6*a(n-5) - a(n-6) + n^6.
Sum_{n>=1} 1/a(n) = 25622179/76545 - 3080*Pi^2/81 + 149600*Pi*tan(sqrt(37)*Pi/2)/(243*sqrt(37)). - Amiram Eldar, Jan 27 2022