A261504 Number of necklaces with n white beads and 10*n black beads.
1, 1, 11, 166, 3091, 63251, 1376738, 31231278, 730421043, 17485161178, 426342182761, 10551652603526, 264383070217234, 6693356751004275, 170957058318902538, 4399826606699783666, 113989308154754290611, 2970465160237643057033, 77808659386282667142686
Offset: 0
Keywords
Links
- Alois P. Heinz, Table of n, a(n) for n = 0..690
- F. Ruskey, Necklaces, Lyndon words, De Bruijn sequences, etc.
- F. Ruskey, Necklaces, Lyndon words, De Bruijn sequences, etc. [Cached copy, with permission, pdf format only]
- Eric Weisstein's World of Mathematics, Necklace
- Wikipedia, Necklace (combinatorics)
- Index entries for sequences related to necklaces
Crossrefs
Column k=10 of A261494.
Programs
-
Maple
with(numtheory): a:= n-> `if`(n=0, 1, add(binomial(11*n/d, n/d) *phi(d), d=divisors(n))/(11*n)): seq(a(n), n=0..25);
-
Mathematica
a[n_] := If[n == 0, 1, DivisorSum[n, Binomial[11*n/#, n/#]*EulerPhi[#]&]/ (11*n)]; Table[a[n], {n, 0, 25}] (* Jean-François Alcover, Mar 28 2017, translated from Maple *)
Formula
a(n) = 1/(11*n) * Sum_{d|n} C(11*n/d,n/d) * A000010(d) for n>0, a(0) = 1.
a(n) ~ 11^(11*n-1/2) / (sqrt(2*Pi) * 10^(10*n+1/2) * n^(3/2)). - Vaclav Kotesovec, Aug 22 2015
Comments