A264984 Even bisection of A263273; terms of A263262 doubled.

0, 2, 4, 6, 8, 10, 12, 22, 16, 18, 20, 14, 24, 26, 28, 30, 64, 46, 36, 58, 40, 66, 76, 34, 48, 70, 52, 54, 56, 38, 60, 74, 32, 42, 68, 50, 72, 62, 44, 78, 80, 82, 84, 190, 136, 90, 172, 118, 192, 226, 100, 138, 208, 154, 108, 166, 112, 174, 220, 94, 120, 202, 148, 198, 184, 130

Offset: 0

Author

Antti Karttunen, Dec 05 2015

Keywords

• nonn

Crossrefs

Cf. A000035, A010673, A010873, A263272, A263273, A264983, A264975.

Programs

Python

from sympy import factorint
from sympy.ntheory.factor_ import digits
from operator import mul
def a030102(n): return 0 if n==0 else int(''.join(map(str, digits(n, 3)[1:][::-1])), 3)
def a038502(n):
    f=factorint(n)
    return 1 if n==1 else reduce(mul, [1 if i==3 else i**f[i] for i in f])
def a038500(n): return n/a038502(n)
def a263273(n): return 0 if n==0 else a030102(a038502(n))*a038500(n)
def a(n): return a263273(2*n) # Indranil Ghosh, May 22 2017

Scheme

(define (A264984 n) (A263273 (+ n n)))

Formula

a(n) = 2 * A263272(n).

a(n) = A263273(2*n).

Other identities. For all n >= 0:

A010873(a(n)) = 2 * A000035(n) = A010673(n).